The answer is B... False. Tansellations that use only one type of regular polygon are not called semi-regular tessellations
Answer:
i believe the answer is 3pi/4
Answer:
25, 26, 27
Step-by-step explanation:
78/3=26, so one number is 26 and the other numbers have to equal 52, so the numbers have to either be 24,25,27,28. 25+27=52,
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
Answer would be D You can have a rational discriminant for an irrational root, but you can also have rational discriminant for a rational root. So C is partially correct.
<span>All prime discriminants will result in an irrational root, but not all irrational roots have prime discriminants </span>