Answer:
The number of solutions to the given set of equations is 0.
Step-by-step explanation:
Number of solutions of a system of equations:
System of equations: ax = b
If a = 0 and b = 0, infinite solutions.
If a = 0 and b != 0, zero solutions.
If a != 0 and b != 0, one solution.
We are given the following system of equations:
y = 7x + 12
y = 7x + 2
So
7x + 12 = 7x + 2
7x - 7x = 2 - 12
0x = -10
a = 0, b != 0, so zero solutions.
The number of solutions to the given set of equations is 0.
The greatest common factor is 10
Hi there!
f(x) = − 4x/5 − 8/5
Hope this helps !
When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.
