Answer:
Quadrant III
Step-by-step explanation:
The attached picture shows graph of 4 such linear functions with the conditions given in the problem. ALL of them DO NOT pass through Quadrant III.
The graphs shown are of the functions:
<em>So, any linear function of the form 
with 
and 
does not pass through Quadrant III. Answer choice 3 is correct.</em>
Answer:
the second one is the answer
put the equation 2x - y = 16 in the form of y = mx + c
2x - y = 16
2x = 16 + y
y = 2x - 16
the slope of this line is 2. the slope of a line perpendicular to it would be the negative reciprocal of 2. in other words, it would multiply with 2 to give -1.
you can form this equation with that info
2x = -1
x = -1/2
OR
you can flip and change the sign (numerator) of 2/1
2/1
= -1/2
In the hundreds place so its 300
C. 118.2
1 and 2 make a complimentary angle, so 2=118.2
2 and 6 are corresponding, so angle 2=angle 6 (118.2 = 118.2)
