Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
3(4x - 3) - 7x = 5x - 9
First, expand your equation so it will be easier to simplify.
Second, multiply (3)(4x) to get 12x.
Third, multiply (3)(-3) to get -9.
Fourth, combine the like terms. (x and -9 alone).
Fifth, subtract (12x + -7x) to get 5x.
Sixth, change 5x + -9 into a subtraction.
Seventh, since both sides are equal, that means that the equation has infinite solutions.
Answer:
B) infinite solutions
1.3 would be considered greater than negative 5. Although 1.3 is a decimal it is still a positive number and positives are worth more than negatives regardless
Answer:
Option D.
Step-by-step explanation:
The give figure is a triangle having hypotenuse h = 40 in.
Now we have to select the scaled figure having dimensions with a scale factor of 
For option A.
Ratio of hypotenuse of both the triangles =

Therefore,this option is not correct
For option B.
Ratio of both the hypotenuse = 
So, option is not correct.
For option C.
Ratio of hypotenuse = 
Therefore, option is not the correct option.
For option D.
Ratio of hypotenuse = 
Therefore, option D is the correct option.