Answer:
The expected number of floors the elevator stops at, not counting the ground floor is =
n*(1-(1-1/n)^m)
Step-by-step explanation:
Here, we want to know the expected number of floors the elevator stops at.
let X1,X2,X3,..Xn are indicator variable for which value =1 if at least one person stops on that floor otherwise value is 0
P(at least one person stops at floor Xj)=1-P(none of m people stops at floor j)
=1-(1-1/n)^m
here total number of floors on elevetor Stops X=X1+X2+X3+...+Xn
hence expected number of floors on elevetor Stops
E(X)=E(X1)+E(X2)+E(X3)...+E(Xn)
=(1-(1-1/n)^m )+(1-(1-1/n)^m )+(1-(1-1/n)^m )+(1-(1-1/n)^m )+..... n times
=n*(1-(1-1/n)^m)
Answer:
Wall of Jericho
Step-by-step explanation:
The Wall of Jericho was a Pre-Pottery Neolithic A (PPNA) defensive or flood protection wall suggested to date to approximately 8000 BC.[1] If interpreted as an "urban fortification", the Wall of Jericho is the oldest city wall discovered by archaeologists anywhere in the world.[2] It is built of undressed stones and is located at the archaeological mound known as Tell es-Sultan, in the city of Jericho on the West Bank.
The topic of this article is the unique Neolithic-age stone wall, the earliest one of its kind. Other walls, such as contemporary house walls, or later, Bronze and Iron Age city walls, are only mentioned for the sake of context.
Answer:
4i + 9 < simplified version
Step-by-step explanation:
3 + 5i + 6 - i =
4i + 9
The first one would be 9.45 I believe
The second one would be 5.50 I believe
The third one would be 5.40 I believe
And the fourth one should be 8.24
Sorry if incorrect
