Answer:
B on the first question and A on the 2nd
Step-by-step explanation:
Mercury: 2.44 × 103 kilometers
Mars: 3.39 × 103 kilometers
Venus: 6.05 × 103 kilometers
Earth: 6.37 × 103 kilometers
Neptune: 2.46 × 104 kilometers
Uranus: 2.54 × 104 kilometers
Saturn: 5.82 × 104 kilometers
Jupiter: 6.99 × 104 kilometers
The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
In the question ,
it is given that
the time taken to vacate the stadium = 20 minutes
number of exits = 25 exits
capacity of the stadium = 25000 spectators .
given that ,
time taken to exit the stadium varies directly with number of spectators and inversely with the number of exits .
time taken ∝ number of spectators ∝ 1/number of exits .
to remove the proportionality sign , we write the constant
time taken = k * (number of spectators)/(number of exits) .
20 = k * 25000/25
20 = k * 1000
k = 20/1000
k = 2/100
k = 1/50 = 0.02
So, to find the time taken for 21,000 spectators to vacate the stadium, if only 15 exits are functional , we use the formula
time taken = (0.02)*(21000/15)
= 0.02*1400
= 28
Therefore , The time taken for 21000 spectators to vacate the stadium , if only 15 exits are functional is 28 minutes .
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The answer is b, r=24 and t = 24\|3
<span>x³ - 4x² - 3x² + 12x + 2x - 8
= x²(x - 4) - 3x(x - 4) + 2(x - 4)
= (x - 4)(x² - 3x + 2)
= (x - 4)(x - 1)(x - 2)
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