What is an irrational number between 5 and 7

Mathematics

1 answer:

oee [108]3 years ago

5 0

Irrational number between 5 and 7 are
$\sqrt{29}$
$\sqrt{35}$
etc

You might be interested in

Triangle ABC = Triangle ADF, AD = 18, BC = 17, DF= [?]

snow_lady [41]

The value of the length DF is 17

<h3>How to determine the length DF?</h3>

The statement Triangle ABC = Triangle ADF means that the triangles ABC and ADF are congruent triangles.

So, we have:

AB = AD

AC = A F

BC = DF

Given that BC = 17;

The equation BC = DF becomes

17 = DF

Rewrite as:

DF = 17

Hence, the value of the length DF is 17

Read more about congruent triangles at:

brainly.com/question/1675117

#SPJ1

5 0

2 years ago

What is the area, in square centimeters, of the shape below? Express your answer as a fraction in simplest form.

Lina20 [59]

4/9 cm^2 and I hope the picture explains it

7 0

3 years ago

PLEASE HELP! I am doing Imagine Math and I need help with this question!

Vaselesa [24]

The bottom left option is when it is reflected over the x axis, the second to last option on the left is when it is reflected of the y axis, and the middle option is when it is reflected over the line y = x

Hope this helps :)

5 0

2 years ago

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to