A piece of paper measures 8.5 inches by 11 inches. Mrs. Wickowitz wants to hang paper on a bulletin board that has a height of 2
4 inches and an area of 1,728 square inches. Which inequality best represents the possible whole numbers of papers, p, that Mrs. Wickowitz could hang? A. p ≤ 12
The area of a piece of paper is 8.5·11 = 93.5 square inches, so the area of the bulletin board is that of ...
1728/93.5 ≈ 18.48
pieces of paper.
The solution is a number greater than 18, so selection D is the only viable choice.
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The bulletin board is 24 inches high and 1728/24 = 72 inches wide. If Mrs. Wickowitz hangs the papers "sideways", then 3 of them will cover 25.5 inches vertically, and 7 of them will cover 77 inches horizontally. That's 3·7 = 21 whole sheets of paper. That, too, matches selection D.
First you want to find the surface area of one box SA=2(l*w)+2(h*l)+2(h*w) SA=2(12*12)+2(15*12)+2(15*12) SA=2(144)+2(180)+2(180) SA=288+360+360 SA=1008 cm² is for one box Multiply by 4 to get for 4 boxes 4*1008=4032 cm²
