Answer:
14 solubility in 200 gram of water at 20 c
Explanation:
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The concentration of [Sn⁺²] will be calculated by first calculating the moles of SnCl₂ added as these moles will give us the moles of [Sn⁺²] ion.
Moles of SnCl₂ = molarity X volume = 0.04 X 2.60 = 0.104 milli moles [as volume is in mL]
The moles of [Sn⁺² = 0.104 mmol
the total volume in solution = volume due to MO + volume due to SnCl₂ + volume due to HCl + volume due to NaCl
Total volume = 8+2.60+5.43+3.73= 19.76 mL
Concentration = moles / volume
concentration [Sn⁺²] = 0.104mmol / 19.76 mL = 0.0053 mol / L
The pH of a solution represents the logarithm of the concentration of hydrogen ions. The more hydrogen ions a solution has the lower its pH will be and we call it an ACID solution. A solution with few (or virtually none) hydrogen ions has a high pH and we call it BASIC solution
