Answer:
hydrogen gas and zinc sulphide
Lunar eclipse occur on a full moon night when the sun earth moon are alinged in a straight or almost straight line in space. anyone on the night side of the earth at the time of the eclipse can see it
<span>100 kilo joules
There are several phases that this problem undergoes and the final answer is the sum of all the energy used for each phase.
Phase 1. Heating of solid ethanol until its melting point.
Phase 2. Melting of the ethanol until it's completely liquid.
Phase 3. Heating of the liquid ethanol until it reaches its boiling point.
Phase 4. Boiling the ethanol until it's completely vapor.
To make things more interesting, some of our constant are per gram and some others are per mole. So let's calculate how many moles of ethanol we have.
Atomic weight carbon = 12.0107
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass ethanol = 2*12.0107 + 6*1.00794 + 15.999 = 46.06804 g/mol
Moles ethanol = 75g / 46.06804 g/mol = 1.628026719 mol
Phase 1. Use the specific heat of solid ethanol and multiply by the number of degrees we need to change by the mass we have. So
0.97 J/g*K * 75 g * (-114c - -120c)
= 0.97 J/g*K * 75 g * 6K
= 436.5 J
Phase 2: Time to melt. Just need the moles and the enthalpy of fusion. So:
1.628026719 mol * 5.02 kJ/mol = 8.172694128 kJ
Phase 3: Heat to boiling. Just like heating to melting, just a different specific heat and temperature
2.3J/g*K * 75g * (78c - -114c)
= 2.3J/g*K * 75g * 192 K
= 33120 J
Phase 4: Boil it to vapor. Need moles and enthalpy of vaporization. So
1.628026719 mol * 38.56 kJ/mol = 62.77671027 kJ
Now let's add them together:
436.5 J + 8.172694128 kJ + 33120 J + 62.77671027 kJ
= 0.4365 kJ + 8.172694128 kJ + 33.120 kJ + 62.77671027 kJ
=104.5059044 kJ
Since the least precise datum we have is 2 significant figures, round the result to 2 significant figures, giving 100 kilo joules.</span>
Answer:
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The empirical formula of c12h24o12 is a carbohydrate.
<h3>Carbohydrate</h3>
A carbohydrate is a biomolecule made up of carbon (C), hydrogen (H), and oxygen (O) atoms, often with a hydrogen-oxygen atom ratio of 2:1 (as in water), and so having the empirical formula Cm(H2O)n (where m may or may not be different from n). All molecules that meet this exact stoichiometric criterion are not, however, automatically categorized as being carbohydrates.
The term is most frequently used in biochemistry, where it is used as a synonym for saccharide, a class of compounds that includes sugars, starches, and cellulose. The four chemical categories of saccharides are monosaccharides, disaccharides, oligosaccharides, and polysaccharides. The smallest carbohydrates, monosaccharides and disaccharides, are sometimes referred to as sugars.
Learn more about carbohydrate here:
brainly.com/question/14614055
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