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lyudmila [28]
2 years ago
7

A student wants to use the lever to lift the book. At

Chemistry
1 answer:
tensa zangetsu [6.8K]2 years ago
6 0
D.
Since d is the furthest point from the fulcrum the least amount of downward force need be applied.
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If the atoms that share electrons have an unequal attraction for the electrons, the bond is called
VLD [36.1K]

Answer:

A polar covalent bond is a covalent bond in which the atoms have an unequal attraction for electrons and so the sharing is unequal. In a polar covalent bond, sometimes simply called a polar bond, the distribution of electrons around the molecule is no longer symmetrical.

Explanation:

7 0
2 years ago
Which are characteristics of natural selection? Select three options.
Luda [366]
Affects populations,
Occurs when there is genetic variation
Selects organisms with certain traits to survive.
5 0
2 years ago
roundup an herbicide manufactured by monsanto has the formula c3h8no5p. how many moles of molecules are there in a 500g sample o
uranmaximum [27]
N= m/Mr Find the Mr of C3H8NO5P and then divide the mass by the Mr. Sorry I don't have periodic table with me so I can't calculate the Mr for you
3 0
3 years ago
Please help my teacher has like given up
NikAS [45]

Answer:

24.47 L

Explanation:

Using the general gas law equation:

PV = nRT

Where;

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = 0.0821 Latm/molK

T = temperature (K)

According to the provided information in this question,

P = 1.0 atm

V = ?

n = 1 mol

T = 25°C = 25 + 273 = 298K

Using PV = nRT

V = nRT ÷ P

V = 1 × 0.0821 × 298 ÷ 1

V = 24.465 ÷ 1

V = 24.465

V = 24.47 L

5 0
3 years ago
How much energy is required to heat 2kg of ice from -5°c to 0°c
balu736 [363]

Explanation:

total heat = Heat required to convert 2 kg of ice to 2 kg of water at 0 °C + Heat required to convert 2 kg of water at 0 °C to 2 kg of water at 20 °C.

Heat=mhfg+mCpΔT

Here, m ( mass of ice) = 2 kg

hfg (latent heat of fusion of ice) = 334 KJ

Cp of water (specific heat) = 4.187 KJ/Kg-K

ΔT(Temperature difference) = 20 °C

Therefore, Heat required = 2 x 334 + 2 x 4.187 x (20 - 0 )

Heat reqd= 835.48 KJ

Therefore, to melt 2 kg of ice 835.48 KJ of heat is required.

4 0
2 years ago
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