Answer:
6 and 10
Step-by-step explanation:
Let a = the first number(3/5 of the second number namely b)
Let b = the number that is 5/3 of a
a=3/5 b
Assuming they are both positive integers, obviously you will have to add 4 to a.
4+a = b
4 + 3/5 b = b
2/5 b = 4
b = 10
a=6
ONLY ASSUMING IF THEY ARE BOTH POSITIVE INTEGERS
Answer:
Linear Function in standard form
Step-by-step explanation:
Ax + By = C
Answer:
Min 31
Q1 38
Median 49
Q3 52
Max 65
Step-by-step explanation:
Max number
Min number
Dndndhhdhbdndjxjdnfbhhhhhj
Answer:
Each coins are quarters of <u>6</u>, nickels of <u>18</u> and the dimes of <u>9</u>.
Step-by-step explanation:
<u><em>There is a mistake in question.</em></u>
The question must be:
A collection of 33 coins having dimes quarters and nickels, <u>there are 3 times as many nickels as quarters, and one-half as many dimes as nickels</u>, all of the coins equal $3.30 how many coins of each kind are there?
Now, to find the number coins of each.
Let the quarters be
.
Nickels be
.
And the dimes be
.
So, the total collection of coins are:

On adding the fractions we get:


Multiplying both sides by 2 we get:

Dividing both sides by 11 we get:

Thus, quarters = 6.
Nickels = 
Dimes = 
Therefore, each coins are quarters of 6, nickels of 18 and the dimes of 9.