Can somebody help me solve for x?

Mathematics

1 answer:

Dahasolnce [82]3 years ago

7 0

Let y = the distance between the top left corner and the bottom right corner

y^2 = 24^2 + 15^2

y^2 = 801

y = 3 * sqrt(89)

Now we can find x.

12^2 + x^2 = (3 * sqrt(89))^2

x^2 = 657

x = 3 * sqrt(73) or 25.63

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Rewrite these in increasing order of length:<br> 133 dm. 433 cm, 308 km, 91 mm

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$\boxed{91mm$

<h2>Explanation:</h2>

First of all, let's transform each measurement into meter knowing the following relationships:

$1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m$

Therefore, we can compute the following:

$\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m$