Question

Find the midpoint of the line segment defined by the points: (5, 4) and (−2, 1)

Answer 1

Answer: The mid point of the line segment is (1.5,2.5).

Step-by-step explanation:

Since we have given that

A (5,4) and B(-2,1) are the end points of the line segment.

We need to find the mid point say 'C':

As we know the formula for "Mid point ":

$C=(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2})\\\\C=\dfrac{5-2}{2},\dfrac{4+1}{2})\\\\C=(\dfrac{3}{2},\dfrac{5}{2})\\\\C=(1.5,2.5)$

Hence, the mid point of the line segment is (1.5,2.5).

Answer 2

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\ \quad \\ \begin{array}{ccccccccc} &&x_1&&y_1&&x_2&&y_2\\ % (a,b) &&(~{{ 5}} &,&{{ 4}}~) % (c,d) &&(~{{ -2}} &,&{{ 1}}~) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ \left( \cfrac{-2+5}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(\frac{3}{2}~~,~~\frac{5}{2} \right)\implies \left(1\frac{1}{2}~~,~~2\frac{1}{2} \right)$