To get the type of car that Sandy can afford after 3 years, we find the future annuity of the his yearly deposits.
amount deposited by Sandy in a month is $260
amount deposited per year=260*12=$3120
time=3years
rate=7.8%
Fv of annuity= P[(1+r)^n-1]/r
substituting our values we get
Fv=3120[(1+0,078)^3-1]/0.078
=10109.06208
The value of a car he can drive is $10109.06208
Answer:
im pretty sure the answer is (k-w)/v = x
1. 30x-2=1x+1
28x=2x
14=x
Answer:

Step-by-step explanation:
Given expression:

The given expression needs to be simplified to the form 
Applying the exponents rule to simplify.

Writing all numbers as product of 3.
⇒ 
Writing each in exponents form.
⇒ 
Using power of a power rule ![[\ (a^x)^y=a^{xy}\ ]](https://tex.z-dn.net/?f=%5B%5C%20%28a%5Ex%29%5Ey%3Da%5E%7Bxy%7D%5C%20%5D)
⇒ 
Using multiplication rule of exponents ![[\ a^x\times a^y=a^{x+y}\ ]](https://tex.z-dn.net/?f=%5B%5C%20a%5Ex%5Ctimes%20a%5Ey%3Da%5E%7Bx%2By%7D%5C%20%5D)
⇒ 
⇒ 
So we have 
∴ 