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daser333 [38]
3 years ago
6

The vitamin necessary for fibrinogen and prothrombin formation (found in green vegetables and released by intestinal bacteria) i

s:
Biology
1 answer:
Volgvan3 years ago
7 0
It is vitamin B, vitamin D, vitamin A, vitamin E, and vitamin K
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An igneous rock is found on the ground and has no identifiable crystals. What is the most likely origin of this rock?molten mate
quester [9]

The answer would be: <u>Molten material that cooled quickly.</u>


Igneous rocks are formed by the cooling of molten material. So we can cross out the last two choices. The rock has no identifiable crystals so it is most likely an Extrusive igneous rock. They form on the surface where they cool quickly.


Those that form underground are called intrusive rocks. They cool slowly allowing enough time for crystal formation.

4 0
3 years ago
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Why can genes be considered derived characters?
aev [14]

A derived character refers to a particular character that is shared by members of a particular population. Genes are considered to be derived characters because THEY ARE TRANSFER FROM GENERATION TO GENERATION FROM PARENTS TO THEIR OFFSPRING. Genes are derived from the DNA molecule of the parents and these are passed to their offspring during the process of cell division in reproduction.


3 0
3 years ago
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In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

4 0
3 years ago
Which of the following is a slow process that changes earth's surface?
Gekata [30.6K]

Answer:

earthquake (i think)

Explanation:

3 0
3 years ago
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Survival of at least a few members of a population after a major environmental change is most dependent on
Naddika [18.5K]
Survival is dependent upon procreation
7 0
3 years ago
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