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3 years ago

Draw a line with the given intercepts x-intercept: 3 y-intercept: -4

Mathematics

1 answer:

krok68 [10]3 years ago

8 0

Just go 3 left from origin and 4 down from origin then it should be negative line.

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3. Use the diagram 2 and 3 are ____ angles 1. complementary 2. vertical 3. right 4. supplementary

Vladimir79 [104]

2 and three are supplementary angles .

#4.

The answer is opposite angles .

Hence there is no option

Bisected angles are equal

$\\ \sf\longmapsto 5x=3x+10$

$\\ \sf\longmapsto 5x-3x=10$

$\\ \sf\longmapsto 2x=10$

$\\ \sf\longmapsto x=\dfrac{10}{2}$

$\\ \sf\longmapsto x=5$

Now

m<ABC

$\\ \sf\longmapsto 5x+3x+10$

$\\ \sf\longmapsto 8x+10$

$\\ \sf\longmapsto 8(5)+10$

$\\ \sf\longmapsto 40+10$

$\\ \sf\longmapsto 50$

5 0

2 years ago

Read 2 more answers

the three sides of a triangle are n, 3n+2, and 4n−4. If the perimeter of the triangle is 54cm, what is the length of each side?

taurus [48]

The lengths of the sides are 7, 23 and 24.

In order to find this, we need to add all of the side lengths together and set equa to 54. This will allow us to solve for n.

n + 3n + 2 + 4n - 4 = 52

8n - 2 = 52

8n = 54

n = 7

This gives us the length of the first side. To solve for the others, plug 7 into the equations.

3n + 2

3(7) + 2

21 + 2

Then the next one.

4n - 4

4(7) - 4

28 - 4

8 0

3 years ago

Read 2 more answers

What is the mode and median of 1,2,1,3,3,5,3,4,5,4,3,2,5,3,1.

tankabanditka [31]

hope it helps uh ....!!!!

8 0

3 years ago

25 POINTS!!!!! REAL ANSWERS ONLY!!!!!!!! I WILL REPORT LINKS AND FAKE/WRONG ANSWERS!!!!!!!

Nonamiya [84]

Answer:

lateral surface area of traingular prism=perimeter of traingle ×length=[5+3+4]×6=72cm²

curved surface area=2[area oftraingle]=2×1/2×4×3

=12cm²

now

total surface area=72cm²+12cm²=84cm²

volume of traingular prism=area of traingle ×length

=1/2×12×3.4×4=81.6cm³

3 0

2 years ago

Consider the universal set R,R, define the interval A=[−7,1],A=[−7,1], interval B=(−1,5),B=(−1,5), and CC be the negative real n

AURORKA [14]

Draw a diagram representing the real number line, and the sets A and B.

According to the diagram:

1. A∪B= [-7, 5)

2. 2. A∩B∩C= (-1, 0)

3. A∩(B∪C)= [-7, 1] ∩ (-INFINITY, 5) = [-7, 1]

4. 4. A^c ∪ B^c∪ C^c= (not A) ∪ (not B) ∪ (not C) =

(-infinity, -7) ∪ (1, infinity) ∪ (-infinity, -1] ∪ [5, infinity) ∪ [0, infinity)

= (-infinity, -1] ∪ (1, infinity ) ∪ [0, infinity) = (-infinity, -1] ∪ [0, infinity)

5. (C−A)∪(B−C)= "in C but not in A" union "in B but not in C"

=(-infinity, -7) ∪ [0, 5)

8 0

3 years ago