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Paladinen [302]
3 years ago
13

The rate constant for this first‑order reaction is 0.150 s−1 at 400 ∘C. A⟶products How long, in seconds, would it take for the c

oncentration of A to decrease from 0.860 M to 0.260 M?
Physics
1 answer:
Afina-wow [57]3 years ago
6 0

Answer : The time taken for the concentration will be, 7.98 seconds

Explanation :

First order reaction : A reaction is said to be of first order if the rate is depend on the concentration of the reactants, that means the rate depends linearly on one reactant concentration.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{[A]_o}{[A]}

where,

k = rate constant  = 0.150s^{-1}

t = time taken for the process  = ?

[A]_o = initial concentration = 0.860 M

[A] = concentration after time 't' = 0.260 M

Now put all the given values in above equation, we get:

0.150s^{-1}=\frac{2.303}{t}\log\frac{0.860}{0.260}

t=7.98s

Therefore, the time taken for the concentration will be, 7.98 seconds

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jasenka [17]

Answer:

1.8 cm

Explanation:

m = mass of the singly charged positive ion = 3.46 x 10⁻²⁶ kg

q = charge on the singly charged positive ion = 1.6 x 10⁻¹⁹ C

\Delta V =Potential difference through which the ion is accelerated = 215 V

v = Speed of the ion

Using conservation of energy

Kinetic energy gained by ion = Electric potential energy lost

(0.5) m v^{2} = q \Delta V\\(0.5) (3.46\times10^{-26}) v^{2} = (1.6\times10^{-19}) (215)\\(1.73\times10^{-26}) v^{2} = 344\times10^{-19}\\v = 4.5\times10^{4} ms^{-1}

r = Radius of the path followed by ion

B = Magnitude of magnetic field = 0.522 T

the magnetic force on the ion provides the necessary centripetal force, hence

qvB = \frac{mv^{2} }{r} \\qB = \frac{mv}{r}\\r =\frac{mv}{qB}\\r =\frac{(3.46\times10^{-26})(4.5\times10^{4})}{(1.6\times10^{-19})(0.522)}\\r = 0.018 m \\r = 1.8 cm

5 0
3 years ago
9. A plane starts at rest & accelerates along the ground before takeoff. It
Phoenix [80]

Answer:

  9.877 m/s^2

Explanation:

The acceleration can be computed from ...

  d = (1/2)at^2

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6 0
4 years ago
During a supernova, the outer layers of a star are blown off and the star's core shrinks down by a factor of 10,000 or more to f
Lana71 [14]

Answer:

a. the core will spin faster.

Explanation:

By law of conservation of angular momentum

(mvR)i= (mvR)f

m= mass of star

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R= radius of star

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f= final

since, size(R) of the star is reduced by factor of 10,000 and mass remains the same, the velocity must increase by the same factor to keep the angular momentum conserved.

Hence, a. the core will spin faster.

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A snail crawls at a speed of 0.0004 m/s. How long will ot take to climb a garden stick 1.6m high?​
tekilochka [14]

4000 seconds

Explanation:

speed = distance / time

0.0004m/s = 1.6m / time

Subject time

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Hope this helps. Mark as brainliest if possible. tks

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Answer:

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