Answer:
unloosen the tight attire parts,open all windows for better air circulation,if he/she does not react place your hands on the chest and press gently three times per interval while giving them air through the mouth CPR then when they react place them to lie horizontal face sideways
They are falling under the sole influence of gravity all objects<span> will </span>fall<span> with the </span>same<span> rate of </span><span>acceleration needless of there size</span>
Answer:
The answer is "
".
Explanation:
Cavity and benzene should be extended in equal quantities.
![\to 1.18 \times 10^{-3}\times (1+ \Delta T \times 0.000051) = 1.1\times 10^{-3} \times (1+ \Delta T \times 0.00124)\\\\\to (\frac{1.18}{1.1})\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072\times (1+ \Delta T \times 0.000051) = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 = 1+ \Delta T \times 0.00124\\\\ \to 1.072+ \Delta T \times 0.000054672 - 1- \Delta T \times 0.00124=0\\\\](https://tex.z-dn.net/?f=%5Cto%201.18%20%5Ctimes%2010%5E%7B-3%7D%5Ctimes%20%281%2B%20%5CDelta%20T%20%5Ctimes%200.000051%29%20%3D%201.1%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%20%281%2B%20%5CDelta%20T%20%5Ctimes%200.00124%29%5C%5C%5C%5C%5Cto%20%20%28%5Cfrac%7B1.18%7D%7B1.1%7D%29%5Ctimes%20%281%2B%20%5CDelta%20T%20%5Ctimes%200.000051%29%20%3D%201%2B%20%5CDelta%20T%20%5Ctimes%200.00124%5C%5C%5C%5C%20%5Cto%201.072%5Ctimes%20%281%2B%20%5CDelta%20T%20%5Ctimes%200.000051%29%20%3D%201%2B%20%5CDelta%20T%20%5Ctimes%200.00124%5C%5C%5C%5C%20%5Cto%201.072%2B%20%5CDelta%20T%20%5Ctimes%200.000054672%20%3D%201%2B%20%5CDelta%20T%20%5Ctimes%200.00124%5C%5C%5C%5C%20%5Cto%201.072%2B%20%5CDelta%20T%20%5Ctimes%200.000054672%20-%201-%20%5CDelta%20T%20%5Ctimes%200.00124%3D0%5C%5C%5C%5C)
![\to 0.072+ \Delta T \times 0.000054672 - \Delta T \times 0.00124=0\\\\ \to 0.072+ \Delta T ( 0.000054672 -0.00124)=0\\\\ \to \Delta T ( 0.000054672 -0.00124)= -0.072\\\\ \to \Delta T = -\frac{0.072}{( 0.000054672 -0.00124)}\\\\ \to \Delta T = -\frac{0.072}{-0.001185328 }\\](https://tex.z-dn.net/?f=%5Cto%200.072%2B%20%5CDelta%20T%20%5Ctimes%200.000054672%20-%20%5CDelta%20T%20%5Ctimes%200.00124%3D0%5C%5C%5C%5C%20%5Cto%200.072%2B%20%5CDelta%20T%20%28%200.000054672%20-0.00124%29%3D0%5C%5C%5C%5C%20%5Cto%20%5CDelta%20T%20%28%200.000054672%20-0.00124%29%3D%20-0.072%5C%5C%5C%5C%20%5Cto%20%5CDelta%20T%20%3D%20-%5Cfrac%7B0.072%7D%7B%28%200.000054672%20-0.00124%29%7D%5C%5C%5C%5C%20%5Cto%20%5CDelta%20T%20%3D%20-%5Cfrac%7B0.072%7D%7B-0.001185328%20%7D%5C%5C)
![\to \Delta T = \frac{0.072}{0.001185328 }\\\\ \to \Delta T = 60.74^{\circ}\\](https://tex.z-dn.net/?f=%5Cto%20%5CDelta%20T%20%3D%20%5Cfrac%7B0.072%7D%7B0.001185328%20%7D%5C%5C%5C%5C%20%5Cto%20%5CDelta%20T%20%3D%2060.74%5E%7B%5Ccirc%7D%5C%5C)
Answer: The distance between the man and the plane increasing at a rate of 400ft/s
Explanation: Please see the attachments below