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astraxan [27]
3 years ago
12

I need help with part D

Physics
1 answer:
natka813 [3]3 years ago
8 0
1).  The little projectile is affected by friction all the way through the block.
Friction robs some kinetic energy.

2).  The block is affected by friction as it scrapes along the top of the post.
Friction robs some kinetic energy.

3).  The block is also affected by friction with the air (air resistance) as it
falls to the ground.  Friction robs some kinetic energy.
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What is the wavelength of an electromagnetic wave?
gizmo_the_mogwai [7]

Answer: (A) The number of waves that pass a point in a certain amount of time.  

Explanation:

Electromagnetic waves are categorized according to their frequency f or, equivalently, according to their wavelength λ = c/f. Visible light has a wavelength range from ~400 nm to ~700 nm.

Frequency: Is the number of waves that pass a certain point in a specified amount of time.

Trough: The low point of the wave cycle.

Wavelength: The distance between two successive peaks.

Electromagnetic wave: One of the waves that are propagated by simultaneous periodic variations of electric and magnetic field intensity.

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2 years ago
Can someone help me please?
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Answer:

The starting position is 3 m and the object is traveling at 3 m/s

Explanation:

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4 years ago
You take a couple of capacitors and connect them in series, to which you observe a total capacitance
Zepler [3.9K]

Answer:

Approximately \rm 5.7\; \mu F and approximately 29\; \rm \mu F.

Explanation:

Let C_1 and C_2 denote the capacitance of these two capacitors.

When these two capacitors are connected in parallel, the combined capacitance will be the sum of C_1 and C_2. (Think about how connecting these two capacitors in parallel is like adding to the total area of the capacitor plates. That would allow a greater amount of charge to be stored.)

C(\text{parallel}) = C_1 + C_2.

On the other hand, when these two capacitors are connected in series, the combined capacitance should satisfy:

\displaystyle \frac{1}{C(\text{series})} = \frac{1}{C_1} + \frac{1}{C_2}.

(Consider how connecting these two capacitors in series is similar to increasing the distance between the capacitor plates. The strength of the electric field (V) between these plates will become smaller. That translates to a smaller capacitance if the amount of charge stored (Q) stays the same.)

The question states that:

  • C(\text{parallel}) = 35\; \rm \mu F, and
  • C(\text{series}) = 4.8\; \rm \mu F.

Let the capacitance of these two capacitors be x\; \rm \mu F and y\; \rm \mu F. The two equations will become:

\displaystyle \left\lbrace \begin{aligned}& x + y = 35 \\ & \frac{1}{x} + \frac{1}{y} = \frac{1}{4.8}\end{aligned}\right..

From the first equation:

y = 35 - x.

Hence, the y in the second equation here can be replaced with (35 - x). That equation would then become:

\displaystyle \frac{1}{x} + \frac{1}{35 - x} = \frac{1}{4.8}.

Solve for x:

\displaystyle \frac{x + (35 - x)}{x \, (35 - x)} = \frac{1}{4.8}.

x\, (35 - x) = 4.8.

x^2 - 35 \, x + 168 = 0.

Solve this quadratic equation for x:

x \approx 5.7 or x \approx 29.3.

Substitute back into the equation y = 35 - x for y:

  • x \approx 5.7 and y \approx 29.3, or
  • x \approx 29.3 and x \approx 5.7.

In other words, these two capacitors have only one possible set of capacitances (even though the previous quadratic equation gave two distinct real roots.) The capacitances of the two capacitors would be approximately 5.7\; \rm \mu F and approximately 29\; \rm \mu F (both values are rounded to two significant digits.)

6 0
3 years ago
Rita has two small containers, one holding a liquid and one holding a gas. Rita transfers the substances to two larger container
SVETLANKA909090 [29]

Sample Response: liquids flow freely, they take the shape of the container they are in, but have a definite volume. Like liquids, the shape of a gas changes with the container. This is because the atoms in a gas move rapidly and freely to fill any available space. Unlike liquids, the volume of a gas changes depending on the container it is in.

3 0
4 years ago
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What is the purpose of having a phone?
Rus_ich [418]

Answer:

The cellphone's main purpose is to keep people connected, regardless of the distance that separates them. Cellphones, much like traditional phones, allow you to place and receive calls.

Explanation:

8 0
3 years ago
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