Line segments JK and JL in the xy-coordinate plane both have a common endpoint J (-4,11) and midpoints an M1 (2,16) and M2 (-3,5
) respectively. What is the distance between M1 and M2? Round to the nearest tenth
1 answer:
Answer:
12.1
Step-by-step explanation:
The dashed line joining M₁ and M₂ is the hypotenuse of a right triangle as shown in red below.
The base of the triangle is
x₂ - x₁ = 2 - (-3) = 2+ 3 = 5
The height of the triangle is
y₂ - y₁ = 16 - 5 = 11
We can now use Pythagoras' theorem to calculate distance between the two midpoints.
x² = 5² + 11² = 25 + 121 = 146
x = √146 = 12.1
The distance between M₁ and M₂ is 12.1.
You might be interested in
Answer:
√20 units.
Step-by-step explanation:
Please see attached photo for diagram.
The other leg of the triangle is x as shown in the attached photo.
Using the pythagoras theory, we can obtain the the value of x as follow:
x² = 4² + 2²
x² = 16 + 4
x² = 20
Take the square root of both side.
x = √20 units
Therefore, the value of the other leg x of the triangle is √20 units
