Question

If x-y doesn't equal 0 then x^2-y^2 / x-y =

Answer 1

Recognize the differnce of 2 perfect squares

a²-b²=(a-b)(a+b)

so
$\frac{x^2-y^2}{x-y}=\frac{(x-y)(x+y)}{x-y}=(\frac{x+y}{1})(\frac{x-y}{x-y})=(x+y)(1)=x+y$