If x-y doesn't equal 0 then x^2-y^2 / x-y =

1 answer:

3 0

Recognize the differnce of 2 perfect squares

a²-b²=(a-b)(a+b)

so
$\frac{x^2-y^2}{x-y}=\frac{(x-y)(x+y)}{x-y}=(\frac{x+y}{1})(\frac{x-y}{x-y})=(x+y)(1)=x+y$

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What os the slope of a line that is perpendicular to the line shown

Dmitriy789 [7]

Perpendicular lines have slopes that are negative reciprocals.

so first you must find the slope of the line given
the slope formula is

m=(y₂-y₁)/(x₂-x₁)

now you just plug in the coordinate points that you are given

m=(-2-2)/(0-(-3)
m=-4/3

so the slope of the line given is -4/3, the negative reciprocal of this would be 3/4

The slope of the perpendicular line would be 3/4

7 0

3 years ago

And choose D is 38<br> Some help me

Dmitry_Shevchenko [17]

Answer:A

Step-by-step explanation:

it is equivalent to 180-128 because its the same as the angle under route 2

and above runway 2

4 0

3 years ago

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How to find variables x- and y-

Monica [59]

It says that the triangles are congruent (same size). Also, a triangle's angles add up to 180 degrees. In both of these triangles, one angle is 90° and another angle is 52°. The other angle is 180°-90°-52°=38°.

Solve these equations to find x and y: 2x+18=38, 3y+11=38

$2x+18=38\\2x=20\\x=10$