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puteri [66]
3 years ago
13

Ugh I need help I haven’t been doing my work

Mathematics
1 answer:
DaniilM [7]3 years ago
6 0

Answer:

You should do your homework.

Step-by-step explanation: It's not good if you don't do it.

You might be interested in
HELP PLS!! <br> Adding and subtracting vectors in component form
tino4ka555 [31]
<h3>Answers:</h3>
  1. u+v = <3,12>
  2. w+g = <7,0>
  3. g-z = <2,4>
  4. v-u = <9,4>
  5. y+v = <7,9>
  6. u+v+y = <4,13>

===================================================

Explanation:

Problem 1

If we had the two vectors u = <a,b> and v = <c,d>, then adding them gives us

u+v = <a+c,b+d>

The corresponding coordinates pair up and add together.

In this case we have

u = <-3,4>

v = <6,8>

So,

u+v = <-3+6,4+8>

u+v = <3,12>

---------------------

Problem 2

We follow the same idea as the previous problem.

w = <8,-1>

g = <-1,1>

w+g = <8+(-1),-1+1>

w+g = <7,0>

---------------------

Problem 3

Similar to addition, subtracting vectors has us subtract the corresponding coordinates.

The general template is:

u = <a,b>

v = <c,d>

u-v = <a-c,b-d>

With this in mind, we can say the following:

g = <-1,1>

z = <-3,-3>

g-z = <-1-(-3),1-(-3)>

g-z = <-1+3,1+3>

g-z = <2,4>

---------------------

Problem 4

Follow the same idea as problem 3 above.

v = <6,8>

u = <-3,4>

v-u = <6-(-3),8-4>

v-u = <6+3,8-4>

v-u = <9,4>

---------------------

Problem 5

Refer to problem 1.

y = <1,1>

v = <6,8>

y+v = <1+6,1+8>

y+v = <7,9>

---------------------

Problem 6

u = <-3,4>

h = v+y = y+v = <7,9>

u+v+y = u + h

u+v+y = <-3,4> + <7,9>

u+v+y = <-3+7,4+9>

u+v+y = <4,13>

Notice how I built off the result of problem 5 when I used h = v+y. The vector v+y is the same as y+v because the order of addition doesn't matter. Also, the idea mentioned in problem 1 can be extended for more than two vectors.

3 0
3 years ago
A two-word phrase used to show division in a word problem.
9966 [12]
Not sure which ones you are supposed to know so here are some possible answers:
ratio of,
divided by,
quotient of,
out of.
8 0
3 years ago
In ΔOPQ, the measure of ∠Q=90°, OP = 7.2 feet, and PQ = 5.5 feet. Find the measure of ∠P to the nearest degree.
N76 [4]

Answer:

40

Step-by-step explanation:

DeltaMath

4 0
3 years ago
Find the equation of the line parallel to 2y-3x= 4 and passing through the point (6,7)
frutty [35]

Answer:

We have equation of a line:

2y - 3x = 4 => y = (3/2)x + 4

The equation of the line that is parallel to above line and passes through the point (6, 7) would have form y = ax + b, and

a = 3/2

6a + b = 7

=> b = 7 - 6a = 7 - 6 x 3/2 = 7 - 9 = -2

=> The equation of that line: y = (3/2)x - 2

Hope this helps!

:)

7 0
3 years ago
Can you please help me solve 18 and 21 please?
olya-2409 [2.1K]
<h3>Answer:</h3>

18. x = y = -3

21. y was substituted into the wrong equation. The solution is (x, y) = (2, 1).

<h3>Step-by-step explanation:</h3>

18. Adding y to the first equation transforms it to ...

... x = y

Then you can substitute for either variable in the second equation.

... 2y -5y = 9 . . . . . substitute for x

... -3y = 9 . . . . . . . . simplify

... y = -3 . . . . . . . . . divide by the coefficient of y

.. x = -3 . . . . . . . . . x and y have the same value

___

21. The first equation is being used to find an expression for y in terms of x. If you substitute that expression back into the same equation, it will tell you nothing you didn't already know. (Here, it is telling you 5 = 5.) The expression is only useful if you <em>substitute it into a different equation</em>. Here, it needs to be substituted into the second equation:

... <u>Step 2</u>: 3x -2(-2x+5) = 4 ⇒ 7x -10 = 4 . . . . . substitute for y in the second eqn

... <u>Step 3</u>: 7x = 14 . . . . . add 10

... <u>Step 4</u>: x = 2 . . . . . . . divide by 7

... <u>Step 5</u>: y = -2·2 +5 = 1 . . . . . find the value of y from x using the expression from step 1. Now, you know the solution is (x, y) = (2, 1).

_____

The attached graph shows the solution to the problem of 21.

4 0
3 years ago
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