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3 years ago

Write the equation of a line in point-slope form that has a slope of -1 and passes through the point (-2, 5).

1 answer:

7 0

$The\ point-slope\ form:y-y_1=m(x-x_1)\\----------------------\\m=-1;\ (-2;\ 5)\to x_1=-2;\ and\ y_1=5\\\\\boxed{y-5=-1(x-(-2))\to y-5=-(x+2)}$

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Add. Write your answers in simplest form.<br><br>10 1/6+12 1/10

Scrat [10]

334/15 also known as 22.26

5 0

3 years ago

An apartment complex charges a refundable security deposit when renting an

andriy [413]

Answer:

The monthly rent of the complex = $ 650

and $450 is the security deposit.

Step-by-step explanation:

The amount paid for first month's rent = $1100

Now, let the monthly rent of the complex = $K

So, Deposit on the monthly rent = $ ( K - 200)

Now, according to the question:

$K + $ ( K - 200) = $1100

or, 2K = 1100 + 200

or, K = 1300/2 = 650

or, K = $ 650

Hence, The monthly rent of the complex = $ 650

and the deposit of the rent = K -200 = 650 - 200 = $450

8 0

2 years ago

Suppose an amusement park bought a merry‐go‐round for $92,000. 42,512 people paid $2 each to ride the merry‐go‐round in its firs

tatiyna

Answer: hey

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Hi ! How to solve this question?

tester [92]

You should actually have

$-x^2-4x-10=-(x^2+4x+10)=-(x^2+4x+4+6)=-((x+2)^2+6)=-(x+2)^2-6$

Now, remember that $x^2$ is always non-negative, so $(x+2)^2\ge0$ for any value of $x$ . This means $-(x+2)^2\le0$ for any $x$ , and so

$-(x+2)^2-6\le0-6=-6$

i.e. f(x) is at most -6, and hence negative for all $x$ .

4 0

2 years ago

Average box of crackers is 24.5 ounces with standard deviation of. 8 ounce. What percent of the boxes weigh more than 22.9 ounce

34kurt

Answer:

97.7% of of the boxes weigh more than 22.9 ounces.

15.9% of of the boxes weigh less than 23.7 ounces.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24.5 ounces

Standard Deviation, σ = 0.8 ounce

We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(boxes weigh more than 22.9 ounces)

P(x > 22.9)

$P( x > 22.9) = P( z > \displaystyle\frac{22.9 - 24.5}{0.8}) = P(z > -2)$

$= 1 - P(z \leq -2)$

Calculation the value from standard normal z table, we have,

$P(x > 22.9) = 1 - 0.023 =0.977= 97.7\%$

97.7% of of the boxes weigh more than 22.9 ounces.

b) P(boxes weigh less than 23.7 ounces)

P(x < 23.7)

$P( x < 23.7) = P( z < \displaystyle\frac{23.7 - 24.5}{0.8}) = P(z < -1)$

Calculation the value from standard normal z table, we have,

$P(x < 23.7) =0.159= 15.9\%$

15.9% of of the boxes weigh less than 23.7 ounces.

7 0

3 years ago