Question

I need help with 11 and 12

Answer 1

Answer:

Both are inverse pairs  

Step-by-step explanation:

Question 11

$g(x)= 4 + \dfrac{8}{5}x$

(a) Rename g(x) as y  

$y = 4 + \dfrac{8}{5}x$

(b) Solve for x :  

$\dfrac{8}{5}x = y - 4$

(c) Multiply each side by ⅝

$x = \dfrac{5}{8}(y - 4) = \dfrac{5}{8}y - \dfrac{5}{2}$

(d) Switch x and y  

$y = \dfrac{5}{8}x - \dfrac{5}{2}$

(e) Rename y as the inverse function  

$g^{-1}(x) = \dfrac{5}{8}x - \dfrac{5}{2}$

(f) Compare with your function

$f(x) = \dfrac{5}{8}x - \dfrac{5}{2}\\\\f(x) = g^{-1}(x)$

f(x) and g(x) are inverse functions.

The graphs of inverse functions are reflections of each other across the line y = x.

In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)

 

Question 12

h(x)= x - 2

(a) Rename h(x) as y  

y = x - 2

(b) Solve for x:  

x = y + 2

(c) Switch x and y  

y  = x + 2

(e) Rename y as the inverse function  

h⁻¹(x) = x + 2

(f) Compare with your function

f(x) = x + 2

f(x) = h⁻¹(x)

h(x) and ƒ(x) are inverse functions.

The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).