Sin2x = 2sinxcosx;
cos2x = (cosx)^2 - (sinx)^2;
tan2x = (sin2x)/(cos2x);
cosx = 5/13 from formula (sinx)^2 + (cosx)^2 = 1;
=> sin2x = 120/169;
.................................
123/0.75 =164
the answer is 164
The answer is
B. -2 and 3
Step-by-step explanation :
Given the expression
x²- 5x + 6 = 0
Firstly we need to find two numbers that when multiplied will give us the constant term 6, and when added will give us the 2nd term 5
These numbers are 3 and 2
Substituting 2x +3x for 5x
x²- (2x+3x)+ 6 = 0
x²-2x-3x+6=0
(x²-2x)-(3x+6)=0
Factoring we have
x(x-2)-3(x-2)=0
x-3=0, x-2=0
x=3, x= 2
Answer:A for the first one and C for the second one
Step-by-step explanation:
