%7D%7B4%7D%20%7D%20%20%5Ctimes%20%28%28%20%5Cfrac%7B4%7D%7B25%7D%29%20%7B%7D%5E%7B%20%5Cfrac%7B3%7D%7B2%7D%20%7D%20%20%5Cdiv%20%28%20%5Cfrac%7B5%7D%7B2%7D%20%29%20%7B%7D%5E%7B%20-%203%7D%20" id="TexFormula1" title="simplify \: ( \frac{81}{16} ) { }^{ \frac{ - 3}{4} } \times (( \frac{4}{25}) {}^{ \frac{3}{2} } \div ( \frac{5}{2} ) {}^{ - 3} " alt="simplify \: ( \frac{81}{16} ) { }^{ \frac{ - 3}{4} } \times (( \frac{4}{25}) {}^{ \frac{3}{2} } \div ( \frac{5}{2} ) {}^{ - 3} " align="absmiddle" class="latex-formula">
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Answer:
The length of the angle bisector of angle ∠A is 6.01.
Step-by-step explanation:
It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.
Using pythagoras theorem
Bisector divides the angle in two equal parts, therefore,
In triangle ACD.
Therefore the length of the angle bisector of angle ∠A is 6.01.
