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Answer:
The speed of the stone when it is 4.66 m higher is 236.057 m/s.
Explanation:
Given the initial velocity and vertical distance, we can use the fourth kinematic equation () to find v final, or the v to the left of the equal sign. We know
(initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8
.
From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.
To isolate v final, we can take the square root of and do the same to the right side of the equation. Therefore, we can find v final with:
, where v initial is outside of the square root because it squared...
If we plug in the known values to the simplified equation, we get:
The final answer is 236.057 m/s.
The cyclist is moving by uniformly accelerated motion, with an initial velocity of 
and an acceleration of 
.
The acceleration is given by
where
is the final velocity and 
is the time between the end and the beginning of the motion, and in our case it is 1.75 s. Therefore, from this relationship we can find the final velocity:
The acceleration is given by
where