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andrew-mc [135]
2 years ago
5

A stone is thrown vertically upward with an initial speed of 24.7 m/s. Neglect air resistance. The speed of the stone when it is

4.66 m higher is:
Physics
1 answer:
fredd [130]2 years ago
4 0

Answer:

The speed of the stone when it is 4.66 m higher is 236.057 m/s.

Explanation:

Given the initial velocity and vertical distance, we can use the fourth kinematic equation (v^{2} =v_{o}^{2}+2ay) to find v final, or the v to the left of the equal sign. We know v_{o} (initial velocity) is 24.7 m/s, y (change in vertical distance) is 4.66 m, and a is another way to write g (acceleration due to gravity), or 9.8 m/s^{2}.

From here you could plug in the values and solve for v final, but to make the solving process simpler, we can simplify the given equation, <em>then </em>plug in the known values.

To isolate v final, we can take the square root of v^{2} and do the same to the right side of the equation. Therefore, we can find v final with: v_{o} \sqrt{2ay}, where v initial is outside of the square root because it squared...

If we plug in the known values to the simplified equation, we get: v=24.7m/s*\sqrt{2(9.8m/s)(4.66 m)}

The final answer is 236.057 m/s.

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If it took 3 hours to clean 6 houses, how many houses could be cleaned in 12 hours?
mel-nik [20]

Answer:

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Explanation:

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To calculate this, we can think about how we go from 3 to 12. Well, 3x4 is 12, so we got to 12 by doing multiplying by 4. So we can multiply 6 by 4 and you get 24.

<u><em>Hope it helps! have a great day :)</em></u>

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