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3 years ago

9

a net force of 25 newtons is applied horizontally to 10. -kilogram block resting on a table. what is the magnitude of the accele

ration of the block?

1 answer:

Pavel [41]3 years ago

4 0

Answer:2.5m/s^2

Explanation:

Acceleration=force/mass

A=25/10

A=2.5

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A hawk in level flight 135m above the ground drops the fish it caught. If the hawk horizontal speed is 20m/s, how far ahead of t

Kaylis [27]

Find how long it will take the fish to hit the ground

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3 years ago

When beryllium-7 ions (m = 11.65 × 10-27 kg) pass through a mass spectrometer, a uniform magnetic field of 0.205 T curves their

AysviL [449]

Answer:

ratio =0.3075 T

Explanation:

The magnetic field B creates a force on a moving charge such that

$F = qvB$

Now this causes a centripetal acceleration

$F = = mv^2/r$

so

$qvB = mv^2/r$ ...........(i)

$B = mv/(rq)$ ...............(ii)

If accelerating potential V is same and then kinetic energy equals the potential energy difference

$\frac{1}{2} mv^2 = Vq$

$v = \sqrt{(2Vq/m)}$ put these value in equation (ii)

$B = m\frac{\sqrt{(2Vq/m)} }{rq}$

simplifying we get

$B =m \frac{(\sqrt{ 2Vm/q})}{r}$

for same location r will be same in both case

$B_{7} = \frac{ \sqrt{(m_{7})(2V/q) }}{r}$ ..............(iii)

$B_{10} = \frac{ \sqrt{(m_{10})(2V/q) }}{r}$ ..........(iv)

dividing (iv) and (iii) equation we get

$\frac{B_{10}}{B_{7}} = \sqrt{\frac{m_{10}}{{m_7}} }$

${B_{10}} = B_{7} \sqrt{\frac{m_{10}}{{m_7}} }$

$B_{10} = 0.2574T\sqrt{\frac{ (1.663x10^-26}{(1.165x10^-26)}$

so on solving we get

=0.3075 T

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3 years ago

Determine the velocity required for a moving object 2.00 x 10^4 m above the surface of Mars to escape from Mars's gravity. The m

Ket [755]

Answer:

Therefore the escape velocity from Mar's gravity is $15.88 \times 10^4$ m/s.

Explanation:

Escape velocity: Escape velocity is a the minimum velocity that a object needs to escape from the gravitational field of massive body.

$V_{escape}=\sqrt{\frac{2GM}{R}}$

$V_{escape}=$ Escape velocity

G=Universal gravitational constant = 6.673×10⁻¹¹N m²/Kg²

M= mass of Mars = 6.42×10²³ kg

R = Radius of the Mars = 3.40×10³m

The escape velocity does not depend on the velocity of a object.

$V_{escape}=\sqrt{\frac{2\times6.673\times 10^{-11}\times 6.42\times 10^{23}}{3.40\times10^3}}$

$=15.88 \times 10^4$ m/s

Therefore the escape velocity from Mar's gravity is $15.88 \times 10^4$ m/s.

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3 years ago

A thermodynamic process occurs, and the entropy of a system decreases. What can be concluded about the entropy change of the env

stepladder [879]

Answer:

It stays the same.

Explanation:

Entropy of a system either increases or remains constant in any process, it never decreases.

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4 years ago

Jimmy is cooking pasta in a pot of water on the stove. He uses a stopwatch to see how long the pasta takes to cook depending on

Alex787 [66]

Answer:

stove

Explanation:

The stove is the independent variable in this question as it does not depend on anything like other variables such as pot, water, temperature and of cause pasta.

The pot depends on the stove, the water depends on the pot and stove, the pasta depends on the water and its temperature.

Cheers.

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3 years ago