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3 years ago

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A FORCE OF 5N ACTS ON A 15 KG BODY INITIALLY AT REST THE WORK DONE BY THE FORCE DURING THE FIRST SECOND OF THE MOTION OF THE BOD

Y IS
a) 5j
b)6j
c)5/6j
d)75j

1 answer:

aleksandr82 [10.1K]3 years ago

3 0

There answer is C 5/6

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A neutron is confined in a one-demensional potential box of width 5.0 x 10^-15 m. Calculate the minimum kinetic energy of the ne

kvv77 [185]

Answer:

$E_1=1.31\times 10^{-12}\ J$

Explanation:

Given that,

Width of a one dimensional potential box, $x=5\times 10^{-15}\ m$

The energy of a particle in one dimensional box is given by :

$E_n=\dfrac{n^2h^2}{8mx^2}$

h = Planck's constant

m = the mass of the proton

For minimum kinetic energy, n = 1

$E_1=\dfrac{(6.63\times 10^{-34})^2}{8\times 1.67\times 10^{-27}\times (5\times 10^{-15})^2}$

$E_1=1.31\times 10^{-12}\ J$

So, the minimum kinetic energy of the neutron is $1.31\times 10^{-12}\ J$ . Hence, this is the required solution.

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3 years ago

A charge of 7.00 mC is placed at opposite corners corner of a square 0.100 m on a side and a charge of -7.00 mC is placed at oth

andrew-mc [135]

Answer:

4.03\times10^{7}N[/tex], 135°

Explanation:

charge, q = 7 mC = 0.007 C

charge, - q = - 7 mC = - 0.007 C

d = 0.1 m

Let the force on charge placed at C due to charge placed at D is FD.

$F_{D}=\frac{kq^{2}}{DC^{2}}$

$F_{D}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1^{2}}=4.41 \times 10^{7}N$

The direction of FD is along C to D.

Let the force on charge placed at C due to charge placed at B is FB.

$F_{B}=\frac{kq^{2}}{BC^{2}}$

$F_{B}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1^{2}}=4.41 \times 10^{7}N$

The direction of FB is along C to B.

Let the force on charge placed at C due to charge placed at A is FA.

$F_{A}=\frac{kq^{2}}{AC^{2}}$

$F_{D}=\frac{9 \times10^{9}\times 0.007 \times 0.007}{0.1 \times\sqrt{2} \times 0.1 \times\sqrt{2}}=2.205 \times 10^{7}N$

The direction of FA is along A to C.

The net force along +X axis

$F_{x}=F_{A}Cos45-F_{D}$

$F_{x}=2.205\times10^{7}Cos45-4.41\times10^{7}=-2.85\times10^{7}N$

The net force along +Y axis

$F_{y}=F_{B}-F_{A}Sin45$

$F_{y}=4.41\times10^{7}-2.205\times10^{7}Sin45=2.85\times10^{7}N$

The resultant force is given by

$F=\sqrt{F_{x}^{2}+F_{y}^{2}}=\sqrt{(-2.85\times10^{7})^{2}+(2.85\times10^{7})^{2}}$

$F = 4.03\times10^{7}N$

The angle from x axis is Ф

tan Ф = - 1

Ф = -45°

Angle from + X axis is 180° - 45° = 135°

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3 years ago

the hot gas lines need to be insulated? A never B always C if they are exposed to cold temperatures that could cause the refrige

muminat

The answer is a because it never needs to be insulated

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3 years ago

I guess but I wanna make sure it’s correct so plz help

Crank

The correct answer is actually D. because rapidly is an adverb of time

I hope I've helped!

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3 years ago

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Explain why an egg cooks more slowly in boiling water in Denver than in New York City. (Hint: Consider the effect of temperature

stiv31 [10]

Answer:

In New York is at ocean level while Denver is at an altitude of 1 mile from ocean level. In this way, the breaking point of water is lower in Denver than in New York, that is, the water will boil at lower temperatures in Denver than in New York. If the breaking point of the water decreases, at this point it will put aside more effort to cook an egg. Now the time required to cook the egg is higher in Denver than in New York.

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