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jeka57 [31]
3 years ago
13

(x) A change in position is called:

Physics
1 answer:
Serga [27]3 years ago
3 0

Answer:

(c) displacement

sure answer...

Hope it helps....Pls mark as Brainliest!!!

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Are the small sized gears only force, speed and distance, only speed
sesenic [268]
If the gears are of different sizes, they can be used to increase the power of a turning force. The smaller wheel turns more quickly but with less force, while the bigger one turns more slowly with more force. Cars and bicycles use gears to achieve amazing speeds our bodies could never match without help.

3 0
3 years ago
Set local ground level to 700 ft, and record the inches of mercury.
pashok25 [27]

The altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

<h3>How to determine the altimeter reading?</h3>

The given parameters are:

  • Ground level = 700 ft i.e. the field elevation
  • Pressure altitude = 1450 ft

The formula to calculate the pressure altitude is:

Altitude = (29.92 – Altimeter reading) * 1,000 + Ground level

Substitute the known values

1450 = (29.92 - Altimeter reading) * 1000 + 700

Evaluate the like terms

750 = (29.92 - Altimeter reading) * 1000

Divide both sides by 1000

0.75 = 29.92 - Altimeter reading

Evaluate the like terms

Altimeter reading = 29.17

Hence, the altimeter reading is 29.17 from the Kollsman window is 29.17 in Hg

Read more about pressure at:

brainly.com/question/26040104

#SPJ1

4 0
2 years ago
When, how and where are questions asked during critical inquiry?*<br> 1 p<br> True<br> False
Ierofanga [76]

Answer:

true

Explanation:

7 0
2 years ago
The potential (relative to infinity) at the midpoint of a square is 3.0 V when a point charge of Q is located at one of the corn
tester [92]

Answer:

12.0 V

Explanation:

Data :

Potential difference due to a single charge (+Q), E = 3.0 V

 

The Electric potential for the system of charges is given as:

E=\frac{1}{4\pi \epsilon_o}[\Sigma\frac{Q}{r}]

for single charge, E = 3.0 V = \frac{1}{4\pi \epsilon_o}[\frac{Q}{r}]  ->eq(1)

And for 4 charges:

E=\frac{1}{4\pi \epsilon_o}[4\frac{Q}{r}] -eq(2)

from eq(1) and (2) we have

E = 4 × 3.0 V = 12 V

5 0
3 years ago
The plates of a parallel-plate capacitor are 700 cm2 in area and 0.3 cm apart. The potential difference between the plates is 93
Kisachek [45]

Answer: a) E = 311,666.7 V/m, b) q = 1.54×10^-10c, c) F = 4.799×10^-5 N, d) 0.0629 J

Explanation:

Area = 700cm² = (700/100)² = 7² = 49m²

Distance between plates (d) = 0.3cm = 0.3/100 = 0.003 m

V = potential difference = 935v

A)

Recall that for a capacitor that V = Ed

Where E = strength of electric field.

935 = E× 0.003

E = 935/ 0.003

E = 311,666.7 V/m

B)

C =qV

Where q = magnitude of charge on capacitor.

We need to get the value for C before we can get for q.

C =ε0×A/d

Where ε0 =permittivity of free space = 8.85×10^-12

Hence we have that

C = 8.85×10^-12 × 49/ 0.003

C = 4.32×10^-10/0.003

C = 1.44×10^-7 F

But C=qV

1.44×10^-7 = q (935)

q = 1.54×10^-10c

C)

F=Eq

Where E = strength of electric field = 311,666.7 V/m, q = 1.54×10^-10c

F = 311,666.7 × 1.54×10^-10

F = 4.799×10^-5 N

D)

Total energy stored = cv²/2

Total energy = 1.44×10^-7 × 935²/2

Total energy = 0.0629 J

4 0
2 years ago
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