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3 years ago

Which term refers to the structure that forms the surface of a cell separating its contents from the outside world

Physics

2 answers:

GaryK [48]3 years ago

8 0

Im pretty sure the answer is C.cell membrane

otez555 [7]3 years ago

8 0

Its definitely cell membrane, because the cell membrane is the outer layer, try looking up a animal cell chart, you'll see a black line around the cell. That black line is a cell membrane, the cell membrane covers over all its contents.

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In the woman's mouth if

Tpy6a [65]

Answer:

hi mate,

interesting question, first of all the pressure is determined by using the following formula:

Pg = p * G * h

where p is the density of the liquid, G is the gravity and h is the height difference, in you case you have:

p = 1015 kg/m3

G = 9.8m/s2

h = 0.085 m

insert these values into the equation above:

Pg = 1015 kg/m3 * 9.8m/s2 * 0.085 m = 849.81 kg·m-1·s-2 or 849.81 pascal

hope it helps, :-)

please mark me as brainliest

7 0

3 years ago

Suppose that an object is moving along a vertical line. Its vertical position is given by the equation L(t) = 2t3 + t2-5t + 1, w

Tatiana [17]

Answer:

The average velocity is

$266\frac{m}{s},274\frac{m}{s}$ and $117\frac{m}{s}$ respectively.

Explanation:

Let's start writing the vertical position equation :

$L(t)=2t^{3}+t^{2}-5t+1$

Where distance is measured in meters and time in seconds.

The average velocity is equal to the position variation divided by the time variation.

$V_{avg}=\frac{Displacement}{Time}$ = Δx / Δt = $\frac{x2-x1}{t2-t1}$

For the first time interval :

t1 = 5 s → t2 = 8 s

The time variation is :

$t2-t1=8s-5s=3s$

For the position variation we use the vertical position equation :

$x2=L(8s)=2.(8)^{3}+8^{2}-5.8+1=1049m$

$x1=L(5s)=2.(5)^{3}+5^{2}-5.5+1=251m$

Δx = x2 - x1 = 1049 m - 251 m = 798 m

The average velocity for this interval is

$\frac{798m}{3s}=266\frac{m}{s}$

For the second time interval :

t1 = 4 s → t2 = 9 s

$x2=L(9s)=2.(9)^{3}+9^{2}-5.9+1=1495m$

$x1=L(4s)=2.(4)^{3}+4^{2}-5.4+1=125m$

Δx = x2 - x1 = 1495 m - 125 m = 1370 m

And the time variation is t2 - t1 = 9 s - 4 s = 5 s

The average velocity for this interval is :

$\frac{1370m}{5s}=274\frac{m}{s}$

Finally for the third time interval :

t1 = 1 s → t2 = 7 s

The time variation is t2 - t1 = 7 s - 1 s = 6 s

Then

$x2=L(7s)=2.(7)^{3}+7^{2}-5.7+1=701m$

$x1=L(1s)=2.(1)^{3}+1^{2}-5.1+1=-1m$

The position variation is x2 - x1 = 701 m - (-1 m) = 702 m

The average velocity is

$\frac{702m}{6s}=117\frac{m}{s}$

5 0

3 years ago

It is very efficient to drive a large truck to and from school. Please select the best answer from the choices provided T F I th

cestrela7 [59]

It's 100% false, it wastes a ton (sorry for the bad pun!) of gas.

8 0

3 years ago

Read 2 more answers

In an ideal gas, collisions between molecules

chubhunter [2.5K]

Answer:

IDHHHHH

Explanation:

vfdvbggggggggggrhhhhhttttttfdsgt

5 0

3 years ago

You decide to clean the bathroom. You notice that the shower is covered in a strange green slime. You decide to try to get rid o

topjm [15]

The lemonade juice and water.

6 0

3 years ago