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2 years ago

Explain how geothermal energy and tidal energy can be used effectively?

2 answers:

4 0

heating and cooling buildings through geothermal heat pumps, generating electricity through geothermal power plants, and heating structures through direct-use

tidal streams, barrages, and tidal lagoons.

Vadim26 [7]2 years ago

3 0

Geothermal energy can heat, cool, and generate electricity: Geothermal energy can be used in different ways depending on the resource and technology chosen—heating and cooling buildings through geothermal heat pumps, generating electricity through geothermal power plants, and heating structures through direct-use applications.

Tidal can be harnessed in three different ways; tidal streams, barrages, and lagoons.

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Professor Sanchez believes that children acquire language through reinforcement from adults, especially their parents. He believ

MArishka [77]

The answer is “behaviorist”

4 0

3 years ago

4. Think back to Coulomb's Law. Two coins with identical charges are placed on a lab table 1.35 m apart.

FinnZ [79.3K]

A) To calculate the charge of each coin, we must apply the expression of the Coulomb's Law:

F=K(q1xq2)/r²

F: The magnitud of the force between the charges. (F=2.0 N).
K: Constant of proporcionality of the Coulomb's Law (K=9x10^9 Nxm²/C²).
q1 and q2: Electrical charges.
r: The distance between the charges (r=1.35 m).

We have the values of F, K and r, so we can calculate q1xq2, because both coins have identical charges:

q1xq2=(r²xF)/K
q1xq2=(1.35 m)²(2.0 N)/9x10^9 Nxm²/C²
q1xq2=3x10^-10 C
q1=q2=(3x10^-10 C)/2

Then, the charge of each coin, is:

q1=1.5x10^-10 C

q2=1.5x10^-10 C

B) Would the force be classified as a force of attraction or repulsion?

It is a force of repulsion, because both coins have identical charges and both are postive. In others words, when two bodies have identical charges (positive charges or negative charges), the force is of repulsion.

5 0

3 years ago

Read 2 more answers

A jet airliner moving initially at 548 mph

sasho [114]

Let's choose the "east" direction as positive x-direction. The new velocity of the jet is the vector sum of two velocities: the initial velocity of the jet, which is

$v_1 =548 mph$ along the x-direction

$v_2 = 343 mph$ in a direction $67^{\circ}$ north of east.

To find the resultant, we must resolve both vectors on the x- and y- axis:

$v_{1x}= 548 mph$

$v_{1y}=0$

$v_{2x} = (343 mph)( cos 67^{\circ})=134.0 mph$

$v_{2y} = (343 mph)( sin 67^{\circ})=315.7 mph$

So, the components of the resultant velocity in the two directions are

$v_{x}=548 mph+134 mph=682 mph$

$v_{y}=0 mph+315.7 mph=315.7 mph$

So the new speed of the aircraft is:

$v=\sqrt{v_x^2+v_y^2}=\sqrt{(682 mph)^2+(315.7 mph)^2}=751.5 mph$

3 0

3 years ago

Um ônibus percorre a distância de 480 km, entre Santos e Curitiba, com velocidade escalar média de 80 km/h. De Curitiba a Floria

Mariulka [41]

Answer:

10 h

Explanation:

velocidade é a taxa de variação da distância no tempo. é a razão entre a distância e o tempo

de Santos e Curitiba:

distância (d) de 480 km, velocidade (s) de 80 km/h

$s=\frac{d}{t}\\ t=\frac{d}{s} =\frac{480}{80}=6h$

de Curitiba e Florianópolis:

distância (d) de 300 km, velocidade (s) de 75 km/h

$s=\frac{d}{t}\\ t=\frac{d}{s} =\frac{300}{75}=4h$

tempo médio de ônibus entre Santos e Florianópolis = 6h + 4h = 10h

7 0

3 years ago

Read 2 more answers

In certain ranges of a piano keyboard, more than one string is tuned to the same note to provide extra loudness. For example, th

Georgia [21]

Explanation:

Given that,

Frequency in the string, f = 110 Hz

Tension, T = 602 N

Tension, T' = 564 N

We know that frequency in a string is given by :

$f=\dfrac{1}{2L}\sqrt{\dfrac{T}{m/L}}$ , T is the tension in the string

i.e.

$f\propto\sqrt{T}$

$\dfrac{f}{f'}=\sqrt{\dfrac{T}{T'}}$ , f' is the another frequency

${f'}=f\times \sqrt{\dfrac{T'}{T}}$

${f'}=110\times \sqrt{\dfrac{564}{602}}$

f' =106.47 Hz

We need to find the beat frequency when the hammer strikes the two strings simultaneously. The difference in frequency is called its beat frequency as :

$f_b=|f-f'|$

$f_b=|110-106.47|$

$f_b=3.53\ beats/s$

So, the beat frequency when the hammer strikes the two strings simultaneously is 3.53 beats per second.

8 0

3 years ago