the man would only weigh 13.7 kg on the moon
hope i helped:)
Convection. When a fluid such as air or water touches a hot object, it can heat up and then move in bulk as a fluid, thereby carrying the heat quickly to new locations. Hot air rising is a common example of heat convection.
Answer:
The value of the angle is
.
Explanation:
Given:
The condition for diffraction minima is

where,
is the slit-width,
is the angle of incidence,
is the order number and
is the wavelength of the light.
The wavelength of an electron traveling through a medium is governed by de Broglie's hypothesis.
According to de Broglie's hypothesis

Here,
is Planck's constant,
is the mass of the electron and
is the velocity of the electron.
For first minimum
.
From equation (1), we have
![&& a \sin \theta = \dfrac{h}{m_{e}v}\\&or,& \theta = \sin^{-1}[\dfrac{h}{am_{e}v}]](https://tex.z-dn.net/?f=%26%26%20a%20%5Csin%20%5Ctheta%20%3D%20%5Cdfrac%7Bh%7D%7Bm_%7Be%7Dv%7D%5C%5C%26or%2C%26%20%5Ctheta%20%3D%20%5Csin%5E%7B-1%7D%5B%5Cdfrac%7Bh%7D%7Bam_%7Be%7Dv%7D%5D)
If the primary wire's power is 10 A and one branch's power is 4 A, another branch's power will be 6A.
According to Kirchhoff's current law (KCL), the total current flowing through a parallel route circuit's junction equals the total current flowing away from it.
Provided that one of the two branches through which power exits the intersection has a flow of 4A, and also that the junction's overall flow entering it is 10A, the entire current going the junction should be 10A.
Consequently, the second wire's power may be expressed as;
I = I1+ I2 [ where I= total current (10A);
I1= current in one branch (4A) &
I2= current in another branch]
⇒I2 = I - I1
⇒I2 = 10A - 4A
⇒I2 = 6A
Therefore, it can be concluded that when the primary wire bears 10A power having 4A in one of its branches, another branch carries 6A power.
Learn more about Kirchhoff's law here:
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Answer: M = 6.13 × 10^18 kg
Explanation:
g = GM/r2,
Where
The mass M of the asteroid = ?
The radius r = 110000 m
g = 0.0338 m/s^2
G is the gravitational constant.
SI units its value is approximately 6.674×10^−11m3⋅kg−1⋅s−2
Using the formula
g = GM/r2
Cross multiply
GM = gr^2
6.674×10^-11M = 0.0338 × 110000^2
M = 408×10^6/6.674×10^-11
M = 6.13 × 10^18 kg