Answer:
12.0 V
Explanation:
Data :
Potential difference due to a single charge (+Q), E = 3.0 V
The Electric potential for the system of charges is given as:
for single charge, E = 3.0 V = ->eq(1)
And for 4 charges:
-eq(2)
from eq(1) and (2) we have
E = 4 × 3.0 V = 12 V
Change in kinetic energy = 3297280 J
Given that,
Mass, m = 920 kg
Speed of a car, v = 92 m/s
Kinetic energy, K = 3,893,440 J
If the speed of a car, V = 36 m/s
Net kinetic energy is given by :
The change in kinetic energy = 3,893,440 - 596160
= 3297280 J
So, the change in kinetic energy of the car is 3297280 J.
f = 692 N
given data:
f =800N
a =1.2 m s^{2}
m= 90 kg
from newton's second law
net force
therefore we have from above equation
ma =F - f
putting all value to get force of friction
1.2*90 = 800 - f
20 °C
Ideal gas law:
PV = nRT
Rearranging:
P / T = nR / V
Since n, R, and V are constant:
P₁ / T₁ = P₂ / T₂
488.2 kPa / T = 468 kPa / 281.15 K
T = 293.29 K
T = 20.1 °C
Rounded, the temperature was 20 °C.