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muminat
3 years ago
6

The potential (relative to infinity) at the midpoint of a square is 3.0 V when a point charge of Q is located at one of the corn

ers of the square. What is the potential (relative to infinity) at the center when each of the other corners is also contains a point charge of Q
Physics
1 answer:
tester [92]3 years ago
5 0

Answer:

12.0 V

Explanation:

Data :

Potential difference due to a single charge (+Q), E = 3.0 V

 

The Electric potential for the system of charges is given as:

E=\frac{1}{4\pi \epsilon_o}[\Sigma\frac{Q}{r}]

for single charge, E = 3.0 V = \frac{1}{4\pi \epsilon_o}[\frac{Q}{r}]  ->eq(1)

And for 4 charges:

E=\frac{1}{4\pi \epsilon_o}[4\frac{Q}{r}] -eq(2)

from eq(1) and (2) we have

E = 4 × 3.0 V = 12 V

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A box is being pushed from the left with a force of 5 N. No force is being applied from the right.
Sergio039 [100]

Answer:

The box will move to the right with increasing speed

Explanation:

According to Newton's second law:

F=ma (1)

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the box in this problem, there is only one force acting on it: a force of 5 N from the left (so, to the right). This means that according to (1) the box will experience an acceleration: the direction of the acceleration is the same as the direction of the net force (so, to the right), therefore the box will move to the right and its speed will continue increasing due to fact that it is being accelerated.

6 0
3 years ago
What is the acceleration experienced by a car that takes 10s to reach 27m/s from rest
Lerok [7]

|acceleration|  =  (change in speed) / (time for the change)

Change in the car's speed = (27 - 0) = 27 m/s
Time for the change  =  10 sec

|acceleration| = (27 m/s) / (10 s)  =  2.7 m/s² .

That's the magnitude of the car's acceleration.
We don't know anything about its direction.
5 0
3 years ago
A child on a skateboard experiences a 75 N force with an acceleration of 1.5 m/s2.
cupoosta [38]

Answer:

The mass of the child + skateboard is 50 kg

Explanation:

In this problem, we can apply Newton's second law:

F = ma

where

F is the net force on a system

m is the mass of the system

a is the acceleration of the system

In this problem, our system is the child + the skateboard. The net force on them is

F = 75 N

and their acceleration is

a=1.5 m/s^2

So we can re-arrange the equation above to find their combined mass:

m=\frac{F}{a}=\frac{75}{1.5}=50 kg

3 0
3 years ago
Explanation A 5000 kg rocket is at rest in deep space. The rocket burns fuel pushing 10kg of exhaust gases rearward at 4000 m/s.
katovenus [111]

Answer:

F = 4000 N

Explanation:

given,

mass of rocket (M)= 5000 Kg

10 Kg gas burns at speed (m)= 4000 m/s

time = 10 s

average force = ?

at the end the rocket is at rest

by conservation of momentum

 M v + m v' = 0

 5000 x v - 10 x 4000 = 0

 5000 v = 40000

    v = 8 m/s

speed of rocket = 8 m/s

now,

we know

change in momentum = F x Δ t

F = \dfrac{m(v_i-v_f)}{\Delta t}

F = \dfrac{5000(8-0)}{10}

      F = 4000 N

Hence, the average force applied to the rocket is equal to F = 4000 N

4 0
3 years ago
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EastWind [94]
A: is potential
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D: is loosing potential energy and gaining kinetic energy
3 0
3 years ago
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