Ask question

Ask question

All categories

3 years ago

8

Naeem needs 1/4 cup of milk to make a carrot cake. He also needs 1/8 cup of milk to make the icing for the cake. What fraction o

f a cup of milk does naeem need in all?

1 answer:

brilliants [131]3 years ago

6 0

Answer:

3/8 cups

Step-by-step explanation:

Total fraction = 1/4 + 1/8

= 2/8 + 1/8

= 3/8

You might be interested in

Please answer with steps thank you :)

mart [117]

200×180 =36,000
36,000 / pi (approx 3.14)= 11,459.1559026

4 0

3 years ago

PLEASE HELP BEST ANSWER ILL GIVE BRAINLIEST!!

MrRa [10]

It’s b) an =-125(-^2/5)^n

4 0

3 years ago

Joshua went kayaking. It cost him $ 15 to rent the kayak. It also cost $ 6 for each hour spent on the lake kayaking. Joshua spen

pishuonlain [190]

Step-by-step explanation:

The total bill will be the sum of the rent and the cost for the total time spent.

$15 + $6 * 2.5

$15 + $15

$30

8 0

2 years ago

Fast answeer plssss thank you thank you

vova2212 [387]

Select all the options because a rectangle can be made of all dimensions.

3 0

3 years ago

Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se

kolbaska11 [484]

Answer:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

Step-by-step explanation:

Given:

The expression to expand is given as:

$(x-3)(x-9)(x-4)$

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

$(a + b)(c + d) = ac + ad + bc + bd$

$(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27$

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

$(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)$

Therefore, the equivalent expression after expanding is given as:

$(x-3)(x-9)(x-4)=x^3-16x^2+75x-108$

3 0

3 years ago