Michael took the return trip at a velocity 33.75 miles per hour.
<h3>How fast did Michael drive in his return trip?</h3>
Let suppose that Michael drove in <em>straight line</em> road and at <em>constant</em> velocity. Therefore, the speed of the vehicle (v), in miles per hour, can be defined as distance traveled by the vehicle (d), in miles, divided by travel time (t), in hours.
First trip
45 = s / 3 (1)
Second trip
v = s / 4 (2)
By (1) and (2):
45 · 3 = 4 · v
v = 33.75 mi / h
Michael took the return trip at a velocity 33.75 miles per hour.
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The expression equivalent to the expression -90 - 60w is -30(3 + 2w), (-9 - 6w)10 and -20(4.5 + 3w)
We need to find the expressions that are equivalent to given expression
We solve the expression and check,
A) -30(3 + 2w)
-90 - 60w
Yes it is equivalent.
B) (-9 - 6w)10
-90 - 60w
Yes it is equivalent.
C) -3(30 - 20w)
-90 + 60w
No it is not equivalent.
D)(6 + 4w)15
90 + 60w
No it is not equivalent.
E) -20(4.5 + 3w)
-90 - 60w
Yes it is equivalent.
Therefore, The expression equivalent to the expression -90 - 60w is -30(3 + 2w), (-9 - 6w)10 and -20(4.5 + 3w)
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Answer:
68% Confidence interval = [4.5752, 4.5848]
95% Confidence interval = [4.5688, 4.5918]
Step-by-step explanation:
Sample mean (X) = 4.580
Sample Standard Deviation (S) = 0.01065
Sample size (n) = 6
for alpha/2 0.84 = 1.1037
for alpha/2 0.975 = 2.5706
68% Confidence interval = ![[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)]\frac{S}{\sqrt{n}}]](https://tex.z-dn.net/?f=%5Bx-T_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%2C%20x%2BT_%7B%285%29%5D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%5D)
= [4.5752, 4.5848]
95% Confidence interval = ![[x-T_{(5)}\frac{S}{\sqrt{n}}, x+T_{(5)}\frac{S}{\sqrt{n}}]](https://tex.z-dn.net/?f=%5Bx-T_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%2C%20x%2BT_%7B%285%29%7D%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%7D%5D)
= [4.5688, 4.5918]
Answer: 
Step-by-step explanation:
For this exercise you must remember that the original figure (before a transformation) is called "Pre-Image" and the one obtained after the transformation is called "Image".
A Translation is defined as a transformation in which the figure is moved a fixed distance in a fixed direction. In this kind of transformatiosn the size and shape do not change and the figure is not flipped.
In this case you know that the Pre-Image is the Triangle FGH.
You can identify in the picture that its vertex H has these coordinates:
Where:
Since the rule is:
→ 
You can substitute the coordinates of H into the given rule in order to find the coordinates of H'. This is:
Answer:
3π/2 is halfway between π and 2π.
Step-by-step explanation:
3π/2 is halfway between π and 2π.
