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Irina18 [472]
3 years ago
5

For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCL2)

Chemistry
1 answer:
Natasha_Volkova [10]3 years ago
6 0

This is an incomplete question, here is a complete question.

For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCl₂)

Perform the following calculations:

A) Calculate ΔS at 298 K (ΔH= -220 kJ/mol and ΔG= -206 kJ/mol

B) Assuming that ΔS and ΔH change little with temperature, calculate ΔG at 450 K.

Answer :

(a) The value of ΔS at 298 K is, -0.0469 kJ/mol.K

(b) The value of ΔG at 450 K is, -199 kJ/mol

Explanation :

(a) According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy = -206 kJ/mol

\Delta H = enthalpy change  = -220 kJ/mol

\Delta S = entropy change = ?

T = temperature in Kelvin = 298 K

Now put all the given values in the above formula, we get:

-206kJ/mol=-220kJ/mol-298K\times \Delta S

\Delta S=-0.0469kJ/mol.K

Thus, the value of ΔS at 298 K is, -0.0469 kJ/mol.K

(b) According to Gibb's equation:

\Delta G=\Delta H-T\Delta S

\Delta G = Gibbs free energy = ?

\Delta H = enthalpy change  = -220 kJ/mol

\Delta S = entropy change = -0.0469 kJ/mol.K

T = temperature in Kelvin = 450 K

Now put all the given values in the above formula, we get:

\Delta G=-220kJ/mol-450K\times -0.0469 kJ/mol.K

\Delta G=-198.895kJ/mol\approx -199kJ/mol

Thus, the value of ΔG at 450 K is, -199 kJ/mol

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