Answer:
See attachment.
Explanation:
In the first step, a cyclic structure with a positive bromine is formed. The bromine shares the positive charge with the two carbons that it is bonded to, so the carbons are partially positive.
The second bromine atom then attacks the carbon center, coming in from below the first bromine atom ("backside attack") where the antibonding orbital of the second bromine atom is.
The stereochemistry of the mechanism causes the final product to be an anti-dibromocyclohexane.
Chemical change
Hope this helps!
Note that this is occurring at STP, where 22.4L of any gas is equal to 1mol of that gas.
First, convert the liters of O₂ to moles of O₂ using the conversion factor 22.4LO₂ = 1molO₂.
8.6LO₂ × 1molO₂/22.4LO₂
= 8.6/22.4
≈ 0.3839molO₂
Next, convert moles of O₂ to moles of H₂O. In the balanced equation, the coefficients show that there are 2 moles of H₂O for every mole of O₂. So, use the conversion factor 1molO₂ = 2molH₂O.
0.3839molO₂ × 2molH₂O/1molO₂
= 0.3839 × 2
= 0.7678molH₂O
Finally, convert the moles of H₂O to liters of H₂O using the same conversion factor from before, 22.4LH₂O = 1molH₂O.
0.7678molH₂O × 22.4LH₂O/1molH₂O
= 0.7678 × 22.4
≈ 17LH₂O
So, the answer is 17 liters of gaseous water is collected! Note that its rounded to 17 because the measurement given in the problem has 2 sig figs. Hope that helps! :)
adhesion refers to the tendency of unlike molecules to bond with one another
Answer:
d orbital
Explanation:
Given that:-
The principal quantum number, n = 3
The acceptable values of azimuthal quantum number, l are:-
l = 0 , 1 , 2
l = 0 corresponds to s orbital which can accomodate 2 electrons.
l = 1 corresponds to p orbital which can accomodate 6 electrons.
l = 2 corresponds to d orbital which can accomodate 10 electrons.
<u>Thus, the highest energy orbital is: - d orbital</u>
