suppose that you put $2,500 into retirement account that grows with an interest rate of 5.25 % compounded once each year after h
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So an exponential equation is gonna be used for this problem. The formula for such is 
, in which the a variable is the initial value and the b variable is the growth/decay rate.
For this situation, 1200 is gonna be your a variable since you've started out with it. And as for your b variable, its gonna be 107.3%, or 1.073, since it's increasing.
Your equation should look like this:
and from here just plug in 10 into the x variable and solve.
Multiply (1.073)^10 (don't round answers until the end), and take that answer and multiply it with 1200, your answer should be $2427.61.
For this situation, 1200 is gonna be your a variable since you've started out with it. And as for your b variable, its gonna be 107.3%, or 1.073, since it's increasing.
Your equation should look like this:
Multiply (1.073)^10 (don't round answers until the end), and take that answer and multiply it with 1200, your answer should be $2427.61.
Answer: The p-value is 0.154.
Step-by-step explanation:
Since we have given that
We claim that
Null hypothesis :
Alternate hypothesis :
Population mean = 20 hours
Sample mean = 18.5 hours
Sample standard deviation = 4.3 hours
Sample size n = 35
So, test statistic would be
So, the p value would be 0.154.
Hence, the p-value is 0.154.