The graph of the function has no asymptotes.
<h3>The table of values of c(t)</h3>
The function is given as:
c(t) = 5t - t² + 1
When t = 1, 2, 5, 10;
We have:
c(1) = 5(1) - 1² + 1 = 5
c(2) = 5(2) - 2² + 1 = 7
c(5) = 5(5) - 5² + 1 = 1
c(10) = 5(10) - 10² + 1 = -49
So, the table of values is
t c(t)
1 5
2 7
5 1
10 -49
See attachment for the graph of the function
<u>The domain</u>
From the question, we understand that t represents time.
- Time cannot be negative i.e. t ≥ 0
- The time does not exceed 5.2 i.e. t ≤ 5.2
So, the domain is 0 ≤ t ≤ 5.2
<u>The range</u>
From the graph, the maximum of the graph is 7.25
So, the range is 0 ≤ f(t) ≤ 7.25
<u>Asymptotes</u>
From the graph, we can see that the graph has no asymptotes.
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Answer:
+4
Step-by-step explanation:
-5 - (-9)
-5 + 9
4
The question was incorrect. Please find the correct content below.
Compare 32/35 and 9/10.
Comparing 32/35 and 9/10 we have 32/35 is greater than 9/10, that is 32/35 > 9/10.
Fraction is the ratio of two numbers. The upper number is called Numerator and the Lower number is called the Denominator.
We know that if the denominators are the same for two fractions then which has the greatest numerator is a greater fraction than the other.
Given the fractions are 32/35, 9/10
To compare this two fractions we have to make denominators equal first.
LCM of 10,35 = 70
Calculating the fractions,
32/35 = (32*2)/(35*2) = 64/70
9/10 = (9*7)/(10*7) = 63/70
Since 64 > 63
So 64/70 > 63/70
Therefore, 32/35 > 9/10
Hence fraction 32/35 is greater than the other fraction 9/10.
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For this case we have the following product:
We must use the distributive property correctly to solve the problem.
We have then:
Then, we must add similar terms.
We have then:
Answer:
The final product is given by:
option 2
