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igor_vitrenko [27]
3 years ago
15

Determine whether a tangent line is shown in this figure? a. no b. yes

Mathematics
2 answers:
faust18 [17]3 years ago
7 0
No, the tangent line needs to be against the circle from where it leaves. This is just a straight up right angle.
Oksana_A [137]3 years ago
5 0

Answer:

Option B is correct .i.e., Yes.

Step-by-step explanation:

We are given with length of three line segments .

10 , 6 and 8.

We use the result to check if one line is tangent or not.

Result: Tangent is perpendicular to radius at point of contact.

So if AB is tangent than ABO form a right angled triangle and AB is right angle.

AO² = 10² = 100

AB² + BO² = 8² + 6² = 64 + 36 = 100

Since AO² = AB² + BO²

According to Pythagoras theorem,

∠B is 90° which implies AB is tangents to circle.

Therefore, Option B is correct .i.e., Yes.

You might be interested in
MZ1 = _º<br> 140<br> 160<br> 80<br><br><br> what is M
Ilia_Sergeevich [38]

Answer:

80

Step-by-step explanation:

3 0
3 years ago
15) A, B, C, D, E and F are towns situated as follows. * A is 30 km east of D * C is 20 km east of E * F is 10 km west of B * D
harkovskaia [24]

Answer:

Option D: 20km South

Step-by-step explanation:

Lets say A = (0, 0)

  • Finding B:

A is 30km East of D which makes D = (-30, 0)

D is 10km South of F which makes F = (-30, 10)

F is 10km West of B which makes B = (-20, 10)

  • Finding E:

A is 10km North of C which makes C = (0, -10)

C is 20km East of E which makes E = (-20, -10)

  • Finding the answer:

Find distance from B = (-20, 10) to E = (-20, -10)

     1. Cancel equivalent values:

x of B = (-20) and x of E = (-20)

Remove x from equation.

     2. Solve for answer:

B = 10 and E = (-10)

Find the difference: (-10) - 10 = (-20)

Conclusion:

South translates to negative on a graph making the answer 20km South

Hope this helped :)

4 0
2 years ago
Someone help me plz !!!!!
Mrac [35]

Answer:

£1 = 25 hits

Step-by-step explanation:

Will get the equation is

\frac{40}{1000}  =  \frac{1}{x}

so, X=25

x = What we want to find

4 0
3 years ago
given the two points (-24,7) and (30,25) a. What is an equation passing through the points? b. Is (51, 33) also on the same line
kicyunya [14]
Part 1) <span>Given the two points (-24,7) and (30,25) a. What is an equation passing through the points?

step 1
find the slope m
m=(y2-y1)/(x2-x1)----></span>m=(25-7)/(30+24)----> m=18/54----> m=1/3

step 2
wit m=1/3 and the point (30,25)
find the equation of the line
y-y1=m*(x-x1)-----> y-25=(1/3)*(x-30)--->y=(1/3)*x-10+25
y=(1/3)*x+15

the answer Part 1) is
y=(1/3)*x+15

Part 2) <span>Is (51, 33) also on the same line?
</span>if the point (51.33) is on the line y=(1/3)*x+15
then
for x=51 the value of y must be 33
for x=51
y=(1/3)*51+15----> y=17+15----> y=32
32 is not 33 
so
<span>the point does not belong to the given line
</span>
the answer Part 2) is
the point does not belong to the given line

see the attached figure

7 0
3 years ago
Someone pls help me ill give out brainliest pls don’t answer if you don’t know
Alex_Xolod [135]

Answer:

Rectangle shaped cross section is formed by intersection of plane and prism.

Step-by-step explanation:

Given: A rectangular Prism.

To find: Shape of Cross Section when a plane intersect the prism diagonally

A plane intersect the Rectangular prism .i.e, Cuboid diagonally which means plane passes from top edge of cuboid to edge on bottom on opposite side.

Figure is attached.

In this way we get a Rectangular shaped Cross section which includes edges of cuboid and diagonals of the side faces.

Therefore, Rectangle shaped cross section is formed by intersection of plane and prism.

6 0
3 years ago
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