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Kazeer [188]
3 years ago
7

Someone please help me with this!!

Mathematics
1 answer:
Paraphin [41]3 years ago
3 0

PEMDAS tells us to use multiplication and division before addition and subtraction.

<u>-5(8) </u>÷ 10 - <u>14 ÷ 7</u> - <u>(-2)(3)</u>

<u> -40  ÷ 10</u> -     2    -   -6

     <u>-4       -    2 </u>     + 6    <em>two negatives make a positive so - - 6  = + 6</em>

           <u> -6              +6</u>

                      0

Answer: 0


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The sum of three consecutive even numbers is 48. What is the smallest of these numbers?
SVETLANKA909090 [29]

Answer: The numbers are 14, 16 and 18.

Step-by-step explanation: First thing to note is that consecutive even numbers have a difference of 2 units between every two terms. That is, if the first number is a, the next would be a + 2, and the next would be a + 4, and so on.

Therefore the three consecutive even numbers shall be a, a + 2, and a + 4.

Our equation now becomes;

a + a + 2 + a + 4 = 48

3a + 6 = 48

Subtract 6 from both sides of the equation

3a = 42

Divide both sides of the equation by 3

a = 14

Therefore, the numbers are 14, 16 and 18.

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