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Artyom0805 [142]
3 years ago
11

A school has over 500 students, 30 English teachers, and 20 math teachers. What is the ratio between the number of math teachers

and the number of students?
Mathematics
1 answer:
aliina [53]3 years ago
6 0
The ratio is 1:25 (simplified) or 20:500
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If the area of the rectangle below is 126 square meters, find the value of x.
amid [387]

Answer:

x = 5

Step-by-step explanation:

The area (A) o a rectangle is calculated as

A = lb ( l is length and b the breadth ), thus

x² + x - 12 × \frac{x+9}{x-3} = 126 ← factor the quadratic

(x + 4)(x - 3) × \frac{x+9}{x-3} = 126 ← cancel the common factor (x - 3)

(x + 4)(x + 9) = 126 ← expand factors using FOIL

x² + 13x + 36 = 126 ( subtract 126 from both sides )

x² + 13x - 90 = 0 ← in standard form

(x + 18)(x - 5) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 18 = 0 ⇒ x = - 18

x - 5 = 0 ⇒ x = 5

However x > 0 ⇒ x = 5

5 0
4 years ago
What is 68,642 rounded to the nearest thousand?
Sergeeva-Olga [200]
68,642 rounded to the nearest thousand is 69,000.

It's because 68,642 is closer to 69,000 than to 68,000.

I hope it will help you and give a clue for rounding numbers in the future ;)
8 0
3 years ago
Read 2 more answers
Given right triangle QRS, what is the value of sin(30°)?
Eva8 [605]

Answer:

1/2

Step-by-step explanation:

8 0
2 years ago
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The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.
blagie [28]

Answer:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

Step-by-step explanation:

For this case we can define the variable of interest amount of Pb209 and for the half life would be given:

N(t) =N_o (\frac{1}{2})^{\frac{t}{t_{1/2}}}

Where t_{1/2}= 3.3 hr represent the half life and the intial amount would be N_o = 1

And we want to find the time in order to have a 95% of decay so we can set up the following equation:

0.05 = 1 (0.5)^{t/3.3}

If we apply natural log on both sides we got:

ln(0.05) = \frac{t}{3.3} ln (0.5)

And solving for t we got:

t= 3.3 *\frac{ln(0.05)}{ln(0.5)}= 14.26

So then would takes about 14.26 hours in order to have  95% of the lead to decay

4 0
3 years ago
(2y^4)^3 fffffffffffffffffffffffffff
qwelly [4]
Best answer is 8y^12
7 0
4 years ago
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