Answer is (45-25s^2)/(9s^2+6s-45)
Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
Note: In option A, it should be "+" instead of "(".
Given:
The expression is
To find:
The equivalent expression.
Solution:
We have,
Using distributive property, we get
On combining like terms, we get
The expression 
is equivalent to the given expression.
Therefore, the correct option is A.
We can find the slope of this line by using the slope formula:
We'll use the points (-6, 0) and (0, -3)
(-3 - 0) / (0 + 6) = -3/6 = -0.5
The slope of the line is A, -1/2
