I'm assuming a 5-card hand being dealt from a standard 52-card deck, and that there are no wild cards.
A full house is made up of a 3-of-a-kind and a 2-pair, both of different values since a 5-of-a-kind is impossible without wild cards.
Suppose we fix both card values, say aces and 2s. We get a full house if we are dealt 2 aces and 3 2s, or 3 aces and 2 2s.
The number of ways of drawing 2 aces and 3 2s is

and the number of ways of drawing 3 aces and 2 2s is the same,

so that for any two card values involved, there are 2*24 = 48 ways of getting a full house.
Now, count how many ways there are of doing this for any two choices of card value. Of 13 possible values, we are picking 2, so the total number of ways of getting a full house for any 2 values is

The total number of hands that can be drawn is

Then the probability of getting a full house is

Answer:
1st one: -24a-6b-36c
2nd one: 14mn-12m
Step-by-step explanation:
1st one: Multiply '-6' w/ '4a', 'b', and '6c'
2nd one: Multiply '2m' w/ '7n' and '-6'
Answer:
£6655
Step-by-step explanation:
Given data
Principal= £5000
Rate= 10%
Time = 3 years
FInal Amount A=???
The expression for the compound interest is given as
A=P(1+r)^t
substitute
A=5000(1+0.1)^3
A=5000(1.1)^3
A=5000*1.331
A= £6655
Hence the final Amount is £6655
58 plus tip of .20
so
58 times 0.2 = 11.6 is the tip
now we add tax (Presuming we son't tax the tip)
58 times 0.07 = 4.06 the tax
so its
58 + 11.6 + 4.06 = $73.66 total cost