Okay so this is in order of the blanks
matter
potential
kinetic
physical
food.
I think the answer would be Ionic sodium phosphate (Na3PO4) because it has the greatest boiling point elevation.
CH2O2 formic acid I believe so
Answer:
Option (b) "174 nm"
Explanation:
Energy of emitted photon is 7.13 eV.
We need to find the wavelength of the photon.
1 eV = 1.6 × 10⁻¹⁹ J
Energy of a photon is given by :
Where, 
is wavelength of the photon
Putting all the values,
So, the wavelength of the photon is 174 nm.
Answer:
ΔG° = -8.8 kJ/mol
Explanation:
The standard Gibbs free energy of reaction (ΔG°) can be calculated using the following expression.
ΔG° = ΔH° - T.ΔS°
where,
ΔH°: standard enthalpy of reaction
T: absolute temperature
ΔS°: standard entropy of reaction
At 298 K (the temperature that is usually used), ΔG° for the hydrolysis of lactose is:
ΔG° = ΔH° - T.ΔS°
ΔG° = 0.44 kJ/mol - 298 K × 0.031 kJ/mol.K
ΔG° = -8.8 kJ/mol
