From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)
The answer is:
<span>D. Minimum at (2, 3)</span>
Answer:

Step-by-step explanation:
Equation:1
Equation:2
Solving Equation:1

Subtracting 'y' from both the sides:

Putting 'x' in Equation :2

Adding '4' both the sides

Putting the value of 'y' in equation:1


The solution is:

Answer:
g(f(x)) = √(x^2 +17)
Step-by-step explanation:
For ...
f(x) = x^2 +9
g(x) = √(x +8)
The definition of g(f(x)) is ...
g(f(x)) = g(x^2 +9) = √((x^2 +9) +8)
g(f(x)) = √(x^2 +17)
Answer:
136 mm²
Step-by-step explanation:






A = 136