Answer:
The area is 13,3 squared meters
Step-by-step explanation:
The 400 meters of fencing is the perimeter of the area. We know that:
perimeter = 2 (length + width)
or
P = 2 (l+w)
We also know that the length is twice the width, hence:
l = 2w
Substituting this information in the perimeter equation:
P = 2 (2w + w)
P = 4w+2w
P = 6w
w = P/6
Now, the area is defined as:
A = l*w
Therefore,
A = 2*w*w
A = 2 * w^2
Putting the w =P/6 in the previous equation
A = 2 * (P/6)^2
A = 2 * P^2/36
A = P^2/12
And substituting the value of P and doing the math,
A = 13, 333 period 3 which we need to round to 13,3 which is the total number of significant digits given
Complete Question
In ΔVWX, w = 780 cm, ∠X =21° and ∠W=146°. Find the length of x, to the nearest 10th of a centimeter.
Answer:
499.9cm
Step-by-step explanation:
We solve for length x using the Sine rule
w/ sin W = x /sin X
Cross Multiply
x × sin W = w × sin X
x = w × sin X/ sin W
x = 780 × sin 21°/ sin 146°
x = 499.88 cm
Approximately to nearest tenth = 499.9cm
Answer:
x = -2
x= -3
Step-by-step explanation:
x 2+5x+6=0
To solve the equation, factor x^2+5x+6 using formula x^2+(a+b)x+ab=(x+a)(x+b). To find a and b, set up a system to be solved.
a+b=5
ab=6
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 6.
1,6
2,3
Calculate the sum for each pair.
1+6=7
2+3=5
The solution is the pair that gives sum 5.
a=2
b=3
Rewrite factored expression (x+a)(x+b) using the obtained values.
(x+2)(x+3)
To find equation solutions, solve x+2=0 and x+3=0.
x=−2
x=−3
Due to the symmetry of the paraboloid about the <em>z</em>-axis, you can treat this is a surface of revolution. Consider the curve 
, with 
, and revolve it about the <em>y</em>-axis. The area of the resulting surface is then
But perhaps you'd like the surface integral treatment. Parameterize the surface by
with 
and 
, where the third component follows from
Take the normal vector to the surface to be
The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:
Then the area of the surface is
which reduces to the integral used in the surface-of-revolution setup.
