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3 years ago

Nov 19 F

Mathematics

1 answer:

Digiron [165]3 years ago

6 0

Answer:

l.mao you could just send a picture, it's a bit hard to actually answer any of the questions if it's jam-packed like that

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Solve for x, if. 3(x-8)-5=9(x+2)+1 the answer is 7.166 but i don't know how they got it

djverab [1.8K]

The answer and workings are in the document below. Please open it up in a new window to see it in full.

7 0

3 years ago

Read 2 more answers

Please help? I’m super lost...

babunello [35]

Answer:

Step-by-step explanation:

In all of these problems, the key is to remember that you can undo a trig function by taking the inverse of that function. Watch and see.

a. $sin2\theta =-\frac{\sqrt{3} }{2}$

Take the inverse sin of both sides. When you do that, you are left with just 2theta on the left. That's why you do this.

$sin^{-1}(sin2\theta)=sin^{-1}(-\frac{\sqrt{3} }{2} )$

This simplifies to

$2\theta=sin^{-1}(-\frac{\sqrt{3} }{2} )$

We look to the unit circle to see which values of theta give us a sin of -square root of 3 over 2. Those are:

$2\theta =\frac{5\pi }{6}$ and

$2\theta=\frac{7\pi }{6}$

Divide both sides by 2 in both of those equations to get that values of theta are:

$\theta=\frac{5\pi }{12},\frac{7\pi }{12}$

b. $tan(7a)=1$

Take the inverse tangent of both sides:

$tan^{-1}(tan(7a))=tan^{-1}(1)$

Taking the inverse tangent of the tangent on the left leaves us with just 7a. This simplifies to

$7a=tan^{-1}(1)$

We look to the unit circle to find which values of <em>a</em> give us a tangent of 1. They are:

$7\alpha =\frac{5\pi }{4},7\alpha =\frac{\pi }{4}$

Dibide each of those equations by 7 to find that the values of alpha are:

$\alpha =\frac{5\pi}{28},\frac{\pi}{28}$

c. $cos(3\beta)=\frac{1}{2}$

Take the inverse cosine of each side. The inverse cosine and cosine undo each other, leaving us with just 3beta on the left, just like in the previous problems. That simplifies to:

$3\beta=cos^{-1}(\frac{1}{2})$

We look to the unit circle to find the values of beta that give us the cosine of 1/2 and those are:

$3\beta =\frac{\pi}{6},3\beta =\frac{5\pi}{6}$

Divide each of those by 3 to find the values of beta are:

$\beta =\frac{\pi }{18} ,\frac{5\pi}{18}$

d. $sec3\alpha =-2$

Let's rewrite this in terms of a trig ratio that we are a bit more familiar with:

$\frac{1}{cos(3\alpha) } =\frac{-2}{1}$

We are going to simplify this even further by flipping both fraction upside down to make it easier to solve:

$cos(3\alpha)=-\frac{1}{2}$

Now we will take the inverse cos of each side (same as above):

$3\alpha =cos^{-1}(-\frac{1}{2} )$

We look to the unit circle one last time to find the values of alpha that give us a cosine of -1/2:

$3\alpha =\frac{7\pi}{6},3\alpha =\frac{11\pi}{6}$

Dividing both of those equations by 3 gives us

$\alpha =\frac{7\pi}{18},\frac{11\pi}{18}$

And we're done!!!

8 0

3 years ago

Divide write the answer in simplest form

Rom4ik [11]

Answer:

3 is the answer

1/3*9/1=9/3=3

Step-by-step explanation:

6 0

2 years ago

Jenny makes quilts. she can make 7 quilts with 21 yards of material. how many yards of material would be required to make 12 qui

kozerog [31]

3 yards per quilt

36 for 12

8 0

3 years ago

Read 2 more answers

The largest possible circle is cut out of a square whose side length is 8 feet. What will be the approximate area, in square fee

valentina_108 [34]

<h3>Therefore the area of remaining board =13.76 square feet</h3>

Step-by-step explanation:

Given , The length of side of the square is 8 feet.

Since a circle is inscribed in the square. Then the diameter of the circle is equal to the length of side of the square .

Therefore the diameter of the circle is = 8 feet.

Radius of the circle is(r) = $\frac{8}{2}$ feet = 4 feet

The area of the circle is= 3.14 r²

= 3.14 × 4² square feet

= 50.24 square feet

The area of the square is = side × side

= 8×6 square feet

=64 square feet

Therefore the area of remaining board = (64- 50.24)square feet

=13.76 square feet

4 0

3 years ago