Answer:
77460 g
Explanation:
To solve this problem first we<u> convert molecules into moles</u>, using <em>Avogadro's number</em>:
3.47x10²⁶ molecules ÷ 6.023x10²³ molecules/mol = 576.12 moles
Then we <u>convert 576.12 CuCl₂ moles into grams</u>, using its<em> molar mass</em>:
576.12 mol * 134.45 g/mol = 77460 g
So the answer is 77460 g, or 77.46 kg.
Answer: the second one for sure HOPE IT HELPD HAVE A AWSOME DAY :))))))))
Explanation:
Answer:
27.025 g of H₂O
Explanation:
The Balance chemical equation is
2 H₂ + O₂ = 2 H₂O
Step 1: Calculate Limiting Reagent
Moles of H₂
Mole = 16 g / 2.02 g/mol = 7.937 mol
Moles of O₂
Mole = 24 g / 32.00 g/mol = 0.750 mol
Mole ratio of H₂ : O₂ is 2 : 1. Hence, 7.937 mol of H₂ will need 3.9685 mol of O₂. This means O₂ is limiting reagent.
Step 2: Calculate Moles of H₂O
0.750 mol of O₂ will produce 1.50 mol of H₂O because the mole ratio of O₂ : H₂O is 1 : 2.
Step 3: Calculate mass of H₂O
Mass = 1.50 mol × 18.02 g/mol = 27.025 g of H₂O
Answer:
A Bunsen bumper,named after Robert Bunsen, is a kind of gas burner used as laboratory equipment;it produces a single open gas flame ,and used for heating ,sterilization,and combustion. The gas can be natural gas (which is mainly methane) or a liquefied petroleum gas,such as propane,butane,or a mixture
Explanation:
Answer:
3.011 × 10²³ particles
Explanation:
Given data:
Number of moles = 0.5 mol
Number of particles = ?
Solution:
The given problem will solve by using Avogadro number.
It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.
The number 6.022 × 10²³ is called Avogadro number.
one mole of substance = 6.022 × 10²³ particles
For 0.5 mole of substance:
0.5 mol × 6.022 × 10²³ particles / 1 mol
3.011 × 10²³ particles
