Question

If charge on only one object is tripled, determine the new force between them:

Answer 1

Answer:

+3·F

Explanation:

The number of objects in the given system = 2 objects

The charge on each object are; q₁ = -Q, q₂ = -Q

The force acting between the objects = +F

The distance between the objects = 2·d

The formula for the force acting between two charged particles is given as follows;

$F=K \times \dfrac{q_{1} \times q_{2}}{r^{2}}$

Therefore, we get;

$F=K \times \dfrac{-Q \times -Q}{(2\cdot d)^{2}} = K \times \dfrac{Q^2}{4 \cdot d^2}$

By tripling the charge, q₁, on the first object, we get;

q₂ = 3 × (-Q)

$F_2=K \times \dfrac{-3 \cdot Q \times -Q}{(2\cdot d)^{2}} = K \times \dfrac{3 \cdot Q^2}{4 \cdot d^2} = 3 \times +F = +3\cdot F$

Therefore, the new force between them, F₂ = +3·F